The statements true about the the function f(x) = 2x2 – x – 6 are-
- The vertex of the function is (one-quarter, negative 6 and one-eighth).
- The function has two x-intercepts.
<h3>What is vertex of parabola?</h3>
The vertex of parabola is the point at the intersection of parabola and its line of symmetry.
Now the given function is,
f(x) = 2x^2 – x – 6
Also, it is given that the vertex is located at (0.25, -6) and the parabola opens up, the function has two x-intercepts.
Comparing the given function with standard form,
f(x) = a x^2 bx + c
By comprison we get,
a = 2
b = -1
c = -6
Now, x-coordinate of vertex is given as,
x = -b/2a
put the values we get,
x = -(-1)/2*2
or, x = 1/4
Put the value of x in given function, so y-coordinate of the vertex is given as,
f(1/4) = 2(1/4)² - 1/4 - 6
= -49/6
= -6 1/8
Hence, The statements true about the the function f(x) = 2x2 – x – 6 are-
- The vertex of the function is (one-quarter, negative 6 and one-eighth).
- The function has two x-intercepts.
More about vertex :
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Answer:
I can
Step-by-step explanation:
I'm taking precalculus currently
25 is the length of x, using the 30-60-90 special triangle method
You must calculate the length of the segments.
Suppose segments AB and CD
Being A (m, n), B (p, q) C(r,s) and D(t,u)
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They are congruent if:
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If you would like to solve 1/3 / 6, you can do this using the following steps:
1/3 / 6 = 1/3 / 6/1 = 1/3 * 1/6 = 1/18
The correct result would be 1/18.
