Answer:
−
8
r^
13
Step-by-step explanation:
Combine like terms
-4r and 2r= -8r
then add the exponents
5+8=13
THEN SIMPLIFY
-8r^13
Hello,

We know the slope is 2 so :

The equation of the line that passes through the point (5,4) so :




The equation of the line that passes through the point (5,4) and has a slope of 2 is :

<u><em>≡ Solution:</em></u>
<em>⇔ To make it easier:</em>
⇒ ²¹/₂₅ × ⁴/₄
⇒ ⁸⁴/₁₀₀
<u>⇒ 0,84</u>
Answer: (1a) 250° (1b) 70° (2) see below
<u>Step-by-step explanation:</u>
1a) -110 + 360 (one rotation clockwise) = 250°
1b) 430 - 360 (one rotation counterclockwise) = 70°
2) sec Ф = -8/5 in Quadrant III
Quadrant III identifies that both sin (y) and cos (x) are negative.
sec = r/x --> r = 8, x = -5, and y = -√39
(Use Pythagorean Theorem x² + y² = r² to solve for y)
rationalized = 
(GIVEN)
rationalized = 
NOTE THAT YOU ARE ALLOWED A MAXIMUM OF 3 QUESTIONS PER POST. Please repost #3 and #4 as a different question and I will answer them.
Slope is 2 and y intercept is 7