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3 years ago

Cos (-Ø)= √3/3 sinØ <0 what is the value of sinØ?

Mathematics

1 answer:

Inga [223]3 years ago

3 0

Answer:

sin∅= - √6/3

Step-by-step explanation:

Trigonometric function cos is even function which mean:

cos (-∅) = cos ∅

Trigonometric function sin is odd function which mean:

sin (-∅) = - sin∅ => sin∅ < 0

The basic trigonometric equation reads in this case with angle marked ∅:

sin²∅ + cos²∅ = 1 => sin²∅ = 1 - cos²∅ => sin²∅ = 1 - ( √3/3 )² =>

sin²∅ = 1 - (3/9) => sin²∅ = 1 - (1/3) = (3/3) - (1/3) = 2/3 => sin∅ = - √(2/3) =>

sin∅ = - √2/√3 => sin∅ = - √6/3

God with you!!!

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