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kogti [31]
3 years ago
10

Monthly Payment -

Mathematics
2 answers:
algol133 years ago
6 0
I’m pretty sure it’s b
erica [24]3 years ago
6 0

Answer:

i would say A........

Step-by-step explanation:

You might be interested in
Найдите корни уранения |t|:6=4
stiv31 [10]
I think the answer will be t=2/3 or t= -2/3
3 0
3 years ago
makayla has $8 to buy at a school fair each ticket cost $1.50 which inequality best represents how many tickets she can buy
ivolga24 [154]

Answer:

Step-by-step explanation:

If she only has $8, she can't spend more than that.  In other words, she can spend ≤$8.

If each ticket is $1.50 per ticket, the inequality that represents how many tickets she can buy if x represents the number of tickets, is

1.5x ≤ 8

6 0
3 years ago
Waqas wishes to distribute 128 bananas and also 176 apples equally among a certain number of children. find the highest number o
atroni [7]
Answer:
The maximum number of children = 16 

Explanation:
The greatest number of students who can get the fruit in this way (equally) will be equal to the highest common factor between the number of bananas and the number of apples.

Number of bananas = 128 = 2 * 2 * 2 * 2 * 2 * 2 * 2
number of apples     = 176 = 2 * 2 * 2 * 2 *11

We can note that:
the highest common factor = 2 * 2 * 2 * 2 
the highest common factor = 16

This means that the maximum number of children to get both equally is 16

Hope this helps :)
7 0
3 years ago
It cost Liam $6.10 to send 61 text messages. How much would it cost to send 185 text messages?
vredina [299]

Answer:

$18.50

Step-by-step explanation:

In the example before 61 messages = $6.10 or rounding to the tenths place 6.1. If you do the same with 185, you get 18.5 or 18.50

6 0
3 years ago
Read 2 more answers
A patio was to be laid in a design with one tile in the
Vlada [557]

Answer:

10

Step-by-step explanation:

The number of tiles in the design is 1 + 2 + 3 + ...

We can model this as an arithmetic series, where the first term is 1 and the common difference is 1.  The sum of the first n terms of an arithmetic series is:

S = n/2 (2a₁ + d (n − 1))

Given that a₁ = 1 and d = 1:

S = n/2 (2(1) + n − 1)

S = n/2 (n + 1)

Since S ≤ 60:

n/2 (n + 1) ≤ 60

n (n + 1) ≤ 120

n must be an integer, so from trial and error:

n ≤ 10

Mr. Tong should use 10 tiles in the final row to use the most tiles possible.

7 0
2 years ago
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