Answer:
The variance of the temperatures of the 10 day period must be at least zero.
Step-by-step explanation:
The variance is the expectation of the squared deviation of a random variable from its mean. It measures how far a set of numbers are spread out from their average value.
Its unit of measure corresponding to the square of the unit of measure of the variable. In this case, the variance of the temperatures is expressed in (°C)². The variance has a minimum value of 0.
Since the variance is squared, it will always have values greater than zero.
<h2><u>Part A:</u></h2>
Let's denote no of seats in first row with r1 , second row with r2.....and so on.
r1=5
Since next row will have 10 additional row each time when we move to next row,
So,
r2=5+10=15
r3=15+10=25
<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>
r1=5=5+0=5+0×10=5+(1-1)×10
r2=15=5+10=5+(2-1)×10
r3=25=5+20=5+(3-1)×10
<u>So for nth row,</u>
rn=5+(n-1)×10
Since 5=r1 and 10=common difference (d)
rn=r1+(n-1)d
Since 'a' is a convention term for 1st term,
<h3>
<u>⇒</u><u>rn=a+(n-1)d</u></h3>
which is an explicit formula to find no of seats in any given row.
<h2><u>Part B:</u></h2>
Using above explicit formula, we can calculate no of seats in 7th row,
r7=5+(7-1)×10
r7=5+(7-1)×10 =5+6×10
r7=5+(7-1)×10 =5+6×10 =65
which is the no of seats in 7th row.
Answer:
Total overripe fruit = 48
Step-by-step explanation:
<em>Step 1: Assume the value of oranges</em>
Let oranges be x
Oranges = x
Apples = 32 + x
Overripe oranges = 3/5 of oranges
= 3x/5
Overripe apples = 1/3 of apples
= 1/3 (32 + x)
<em>Step 2: Find x (oranges)</em>
<em>Number of overripe apples and number or overripe oranges are equal.</em>
3x/5 = 1/3 (32 + x)
3 (3x) = 5(32 + x)
9x = 160 + 5x
4x = 160
x = 40
<em>Step 3: Find the total number of overripe fruit.</em>
Total overripe fruit = Overripe apples + Overripe oranges
Total overripe fruit = 1/3 (32 + x) + 3x/5
Total overripe fruit = 1/3 (32 + 40) + 3(40)/5
Total overripe fruit = 24 + 24
Total overripe fruit = 48
!!
Answer:
14, 42
Step-by-step explanation:
Set A = {−7, −4, 2, 14, 21, 34, 42}
Set B = {even numbers}
Set C = {multiples of 7}
There is only one question asked
Which numbers in Set A are elements of both Set B and Set C,
We need it to be even and a multiple of 7
14 is even and a multiple of 7 and 42 is even and a multiple of 7
Answer:
wow let me try
Step-by-step explanation:it is a 90% sure
