A=10^x, b=10^yanda^y^*b*x=100then2xy=?
1 answer:
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let's keep in mind that, in the II Quadrant, cosine is negative and sine, is positive.
cosine is adjacent/hypotenuse, however the hypotenuse is simply a radius unit, and thus is never negative, so in the -(2/3) the negative must be the numerator, -2.
Answer:
x=-4
x=6
Step-by-step explanation:
Lets put to work the well known quadratic equation:
Let us also, remember the given equation: x^2-2x-24=0
Where 'a' would be equals to 1, 'b' equals to -2 and c equals to -24.
The quadratic equations with those values is:
Where we obtain two values.
x1= -4
and x2= 6