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professor190 [17]
3 years ago
13

Can you help me with number 10

Mathematics
1 answer:
rewona [7]3 years ago
4 0

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{(3^{-2})^2}{3^{-3}}\implies \cfrac{3^{-2\cdot 2}}{3^{-3}}\implies \cfrac{3^{-4}}{3^{-3}}\implies \cfrac{1}{3^{-3}\cdot 3^4}\implies \cfrac{1}{3^{-3+4}}\implies \cfrac{1}{3^1}\implies \cfrac{1}{3}

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Answer:

<h2>1.5</h2>

Step-by-step explanation:

-----------------------------

Here's how we solve the equation

-1.2\left(3-x\right) = -1.8

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-3.6+1.2\cdot1.5 = -1.8

1.2\cdot1.5 = -1.8

-----------------------------

<em>Hope this helps! <3</em>

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