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3 years ago

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An organisation buys a truck on hire purchase The cost is 500000 The contract states a deposit or 35% and 12 annual payments of

49922 The sum of digs method is used to spread the finance cost (a) How much is the total finance cost? Finance CFinance cost (b) How much interest is charged in the accounts in year 5 of the contract? erest Interest 2 Marks (c) By how much are creditors reduced in year 8 of the contract? Amount Amount 2 Marks

1 answer:

Mama L [17]3 years ago

4 0

Answer:

total finance cost is 274064

interest in 5 year = 17568.21

creditors reduced in year 8 is 21812.87

Step-by-step explanation:

given data

cost = 500000

rate 35%

installment = 12

annual payment = 49922

to find out

the total finance cost and interest is charged in 5 year and creditors reduced in year 8

solution

we know cost is 500000 so down payment will be

payment = 35% of 500000 = 35/100 × 500000

so payment = 175000

and 12 installment purchase price is 12 × 49922

purchase price = 599064

so total finance cost is payment + purchase price - cost

finance cost = 175000 + 599064 - 500000

so total finance cost is 274064

and

we know in 1 to 12 digit sum is 78

so interest in 5 year

interest = 5/78 of total finance cost

interest = 5/78 × 274064

interest in 5 year = 17568.21

and

interest in 8 year

interest = 8/78 of total finance cost

interest = 8/78 × 274064

interest in 8 year = 28109.13

so

creditors reduced in year 8 = 49922- 28109.13

creditors reduced in year 8 is 21812.87

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Answer:

190 baskets of strawberries

Step-by-step explanation:

The question is incomplete as it didn't state what we are to determine from the information given.

Let's determine total amount picked in the three days.

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Amount of strawberries on 2nd day = 2/3 of the amount picked 1st day

= (2/3)(90)

Amount of strawberries on 2nd day = 60 baskets of strawberries

Amount of strawberries picked on 3rd day = (2/3) of the amount picked 2nd day

= (2/3) (60)

Amount of strawberries picked on 3rd day = 40 basket of strawberries

Total amount picked for 3 days = 90+60+40

= 190 baskets of strawberries

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80 90 10 75 90 95 99 find the mean and medain which measures of center best repersents the data

beks73 [17]

Answer:

77

Step-by-step explanation:

sum of all number/total numbers

80+90+10+75+98+95+99/7

77

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3 years ago

What is the GFC of 40 and 60

Svetradugi [14.3K]

Answer:

GCF: 20

Step-by-step explanation:

The thing you want to do is factor both numbers down to their lowest primes.

40:2 * 2 * 2 * 5

60:2 * 2 * 5 * 3

Now underline what is in both sets of primes. I'll bold them. The number that is bolded comes from 2 * 2 * 5 which is 20

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3 years ago

(11w^4 × 3z^9)(2w^7z^2)

mart [117]

Simplified:

11w^4(3)z^9(2w^7z^2)

=66w^11z^11

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Professor Isaac Asimov was one of the most prolific writers of all time. Prior to his death, he wrote nearly 500 books during a

svp [43]

Answer:

Step-by-step explanation:

n = sample size = 5

a) Let us determine the sum

$\sum x_i= 100+200+300+400+490=1490$

$\sum x_i^2= 100^2+200^2+300^2+400^2+490^2=540100$

$\sum y_i = 237+350+419+465+507=1978$

$\sum y_i^2= 237^2+350^2+419^2+465^2+507^2=827504$

$\sum x_i y_i=100 \times 237 + 200\times350+300 \times 419 + 400 \times 465 + 490 \times 507=653830$

Now we can determine $S_x_x, S_x_y, S_y_y$

$S_x_x = \sum x_i^2-\frac{(\sum x_1)^2}{n} \\= 540100 - \frac{1490^2}{5} \\= 96080$

$S_x_y = \sum x_i y_i -\frac{(\sum x_i)(\sum y_i) }{n} \\\\$

$653830 - \frac{1490 \times 1978 }{5} = 64386$

$S_y_y = \sum y_i^2-\frac{(\sum y_i)^2 }{n} = 82750-\frac{1978^2}{5} \\\\= 45007.2$

The estimate b of the slope β is the ratio of $S_x_y$ and $S_x_x$

$b = \frac{S_x_y}{S_x_x}$

$\frac{64386}{96080} = 0.67$

The mean is the sum of all value divide by number of values

$\bar x= \frac{\sum x_i}{n} \\\\= \frac{100+200+300+400+490}{5} \\\\= \frac{1490}{5} = 298$

$\bar y= \frac{\sum y_i}{n} \\\\= \frac{237+350+419+465+507}{5} \\\\= \frac{1978}{5} = 395.6$

The estimate a of the intercept is

$a = \bar y - b \bar x$

$= 395.6 - 0.69 \times 298\\= 195.9$

General least square equation;

$\bar y = \alpha + \beta x$

replace alpha by a = 3 and beta by b = 0.67 in general least equation

y = a + bx

195.9 + 0.67x

b)

<em>Scatter plot is shown in the attached file</em>

x is on the horizontal axis

y is n the vertical axis

The degree of freedom of regression is 1

because we use one variable s predictor variable

$d_f_R = 1$

The degree of freedom of error is the sample size n decrease by 2

$d_f_E =n-2= 5 - 2=3$

Total df is equal to the sum of seperate degree of freedom dfR and dfE

total df = 1 +3 4

$SSR = \frac{(S_x_y)^2}{S_x_x} = \frac{64386^2}{96080} \\\\= 43146.9296$

Total SS =Syy= 45007.2

SSE + Total SS = SSR

= 45007.2 - 43146.9296

= 1860.2705

7 0

3 years ago