When it hits the ground, then h=0
find the xintercept or in this case the tintercepts
c=76
v=135
h=-16t^2+135t+76
use quadratic formula
ax^2+bx+c=0
x=

a=-16
b=135
c=76
x=

x=

x=

aprox
x=-0.5297 or 8.967
exclude the negative root since you can't have negative time
means that it takes 8.97 seconds to hit the ground
To start off, you need to take the cube root of both sides of the equation.
![\sqrt[3]{x} = \frac{ \sqrt[3]{27} }{ \sqrt[n]{64} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%7D%20%3D%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B27%7D%20%7D%7B%20%5Csqrt%5Bn%5D%7B64%7D%20%7D%20)
The cube root of 27 is 3, and the cube root of 64 is 4.
The answer would then be x=3/4
Answer:
omg ikr
Step-by-step explanation:
very sad 2
First, simplify the two inequalities.
2x - 5 < 7
2x < 12 <-- Add 5 to each side
x < 6 <-- Divide both sides by 2
4x + 10 > 6
4x > -4 <-- Subtract both sides by 10
x > -1 <-- Divide both sides 4
Now we have the compound inequality x < 6 OR x > -1
To fulfill the first inequality, x has to be less 6. For the second inequality, x has to bigger than -1.
So, the answer is B. (-infinity, infinity).
Answer:
2
Step-by-step explanation: