The product of any integer and zero
2 answers:
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A statement which proves that the diagonals of square PQRS are perpendicular bisectors of each other is: option D.
<h3>How to calculate the slope of a line?</h3>Mathematically, the slope of a line is given by the following formula;
For line RP, we have:
Slope RP = 7.
For line SQ, we have:
Slope SQ = negative one-sevenths.
For the midpoint, we have:
In order to determine the midpoint of a line segment with two (2) endpoints, we would add each point together and divide by two (2).
Midpoint on x-coordinate = (8 + 1)/2 = 9/2 = 4.5.
Midpoint on y-coordinate = (9 + 2)/2 = 11/2 = 5.5.
In conclusion, a statement which proves that the diagonals of square PQRS are perpendicular bisectors of each other is that the midpoint of both diagonals is (4.5, 5.5), the slope of RP is 7, and the slope of SQ is negative one-sevenths.
Read more on squares here: brainly.com/question/2882032
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Answer:
B. The parent function would be shifted 4 units to the right and 5 units up.
Step-by-step explanation:
Given:
Parent function:
Transformed function:
To find the shifts made to the parent function.
Solution:
Translation Rules:
If the function shifts
units to the left.
If the function shifts
units to the right.
If the function shifts
units to the up.
If the function shifts
units to the down.
From the functions given the translation occurring can be given as:
From the rules we can see that the parent function has moved 4 units to the right and 5 units up.
Given:
Low tide height = 1 ft
High tide height = 5 ft
Tide period, T = 24 houts
Let the height of the tide be modeled by the expression
h(t) = K + A cos(bt)
Because the period is 24, therefore
b = (2π)/24 = π/12
That is,
h(t) = K + Acos[(πt)/12]
When r=0, h = 1, therefore
K + A cos(0) = 1, ot
K + A = 1 (1)
When t = 12 (half cycle), h = 5, therefore
K + A cos(π) = 5, or
K - A = 5 (2)
Add (1) and (2):
2K = 6
K = 3
From(1), obtain
A = 1 - 3 = - 2
Answer:
The required function is h(t) = 3 - 2 cos[(πt)/12]
The amplitude is 2 feet
The period is 24 hours
The midline of the function is h = 3 feet
A graph of the function is shown below.
Low tide height = 1 ft
High tide height = 5 ft
Tide period, T = 24 houts
Let the height of the tide be modeled by the expression
h(t) = K + A cos(bt)
Because the period is 24, therefore
b = (2π)/24 = π/12
That is,
h(t) = K + Acos[(πt)/12]
When r=0, h = 1, therefore
K + A cos(0) = 1, ot
K + A = 1 (1)
When t = 12 (half cycle), h = 5, therefore
K + A cos(π) = 5, or
K - A = 5 (2)
Add (1) and (2):
2K = 6
K = 3
From(1), obtain
A = 1 - 3 = - 2
Answer:
The required function is h(t) = 3 - 2 cos[(πt)/12]
The amplitude is 2 feet
The period is 24 hours
The midline of the function is h = 3 feet
A graph of the function is shown below.