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miv72 [106K]
3 years ago
9

Wooden flooring costs £35 per square metre. The floor is then edged with a narrow wooden strip which costs £4 per metre.

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

£920

Step-by-step explanation:

We need to find the area of floor to find the cost of the flooring, and then we need to find the perimeter of the floor to find the cost of the edging.

A = LW = 6 m × 4 m = 24 m²

Cost of flooring: 24 m² × £35/m² = £840

P = 2(L + W) = 2(6 m + 4m) = 2(10m) = 20 m

Cost of edging: 20 m × £4/m = £80

Total cost:

£840 + £80 = £920

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On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integ
Setler [38]

Answer:\frac{1}{7}

Step-by-step explanation:

Given

sunny day speed= s mph

Rainy day speed=s+1 mph

Derek average speed =2.8 miles/hr

s<2.8<s+1

so on sunny day speed must be 2 mph

and on rainy day speed must be 3 mph

v_{avg}=\frac{distance}{time\ taken}

Let x be the distance traveled in sunny and y be the distance traveled in rainy weather

2.8=\frac{x+y}{\frac}{x}{2}+\frac{y}{3}}

Let \frac{x}{y}=z

2.8=\frac{z+1}{\frac{z}{2}+\frac{1}{3}}

z=\frac{1}{6}

Fraction of distance traveled on sunny weather

\frac{x}{x+y}=\frac{z}{z+1}=\frac{1}{7}

5 0
3 years ago
Three vertices of parallelogram JKLM are J(1, 4), K(5, 3), and L(6,−3). Find the coordinates of vertex M.
Andrej [43]

Answer:

coordinates of vertex M is (x, y) = (2, -2)

Step-by-step explanation:

Since JKLM is a  parallelogram, this implies that JK parallel to LM and KL parallel to JM. This means that

Slope of JK = slope of LM

\frac{3-4}{5-1} =\frac{-3-y}{6-x} \\y=-\frac{1}{4}x-\frac{3}{2} ....(i)

And

Slope of KL = slope of JM

\frac{3-\left(-3\right)}{5-6}=\frac{4-y}{1-x}\\y=10-6x...(ii)

From equation (i) and (ii) we get

-\frac{1}{4}x-\frac{3}{2} =10-6x

-\frac{23x}{4}=-\frac{23}{2}

-23x=-46

x=2

Put the value of x in equation (ii) we get

y=10-6(2)\\y=-2

So, the coordinates of vertex M is (x, y) = (2, -2).

5 0
3 years ago
A company fills a warehouse will two types of goods A and B . they both come in tall boxes which cannot be stocked. one box of A
inessss [21]

Answer:

(1/2) * A + (1/2) * B <= 100; for A => 50; for B => 20

(5000) * A + (30000) * B <= 1500000; for A => 50; for B => 20

Step-by-step explanation:

There are two inequalities in mind, the first of the surface and the second of the price. Always bearing in mind that the minimum are 50 of A and 20 of B.

The first

A occupies 1/2 m and B occupies 1/2 m of surface, and the limit is 100 m of surface. Thus:

(1/2) * A + (1/2) * B <= 100; for A => 50; for B => 20

The second:

A costs 5,000 and B costs 30,000, and the limit is 1,500,000. Therefore:

(5000) * A + (30000) * B <= 1500000; for A => 50; for B => 20

5 0
3 years ago
Helpppppppppppppppp!!!
kirza4 [7]

Answer:

I think it would be 71ft

Step-by-step explanation:

Since the cliff was 85ft and she dove 6 ft underwater, the total distance she traveled was 71ft

3 0
2 years ago
Read 2 more answers
Students deliver catalogues and leaflets to houses. One day they have to deliver 480 catalogues and 1520 leaflets. Each student
solniwko [45]

Answer:

7 students are needed

Step-by-step explanation:

Consider the complete question is,

"Students deliver catalogues and leaflets to houses.One day, they have to deliver 480 C and 1520 L.Each student can deliver either 15 C or 80 L in 1 hour.Each student's can only work for 8 hours.  Work out the minimum number of students needed."

Since, number of catalogues have to deliver = 480,

Number of leaflets have to deliver = 1520,

∵ Each student can deliver 15 catalogues or 80 leaflets in one hour.

Number of hours for working = 8,

So, the catalogues delivered by each student in a day = 15 × 8 = 120,

Similarly, the leaflets delivered by each student in a day = 80 × 8 = 640

Thus, the number of students required to deliver 480 catalogues

=\frac{\text{Total catalogues}}{\text{catalogues delivered by each student in a day}}

=\frac{480}{120}

=4

Again, the number of students required to deliver 1520 leaflets

=\frac{\text{Total leaflets}}{\text{leaflets delivered by each student in a day}}

=\frac{1520}{640}

=2.375

≈ 3 students ( we would approximate above )

Hence, the minimum students required = 4 + 3 = 7

4 0
4 years ago
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