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4 years ago

9

Two parallel lines are crossed by a transversal.

2 answers:

emmasim [6.3K]4 years ago

6 0

Because both lines are parallel, if you add the 5x+5 to the 115 those would equal 180 degrees

so you have 5x+5 + 115 = 180

combine like terms:

5x + 120 = 180

subtract 120 from both sides

5x = 60

x = 60/5
x = 12

olchik [2.2K]4 years ago

6 0

Okay so (5x+5)+115 is going to equal 180.

1.) (5x+5)+115=180

The next steps is to isolate the x.

2.) 5x+120=180
3.) -120=-120
4.) 5x=60
5.) /5=/5
6.) x=12 degrees

Then, you check your work by plugging in the numbers.
7.) 5(12)+5+115=180
8.) 60+5+115=180
9.)180=180

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Help me please !! i need the answer

madam [21]

Answer:

$PQ=22\\\\QR=7\\\\PR=29$

Step-by-step explanation:

To find the value of y, you can create an equation where two parts of the line are equal to the whole line:

$PQ+QR=PR$

Substitute given values:

$(8y+6)+(y+5)=(19y-9)$

Solve for y. Simplify parentheses:

$8y+6+y+5=19y-9$

Combine like terms to simplify the equation:

$8y+y+6+5=19y-9\\\\9y+11=19y-9$

Get the variable on one side of the equation and the constants on the other. Add 9 to both sides:

$9y+11+9=19y-9+9\\\\9y+20=19y$

Subtract 9y from both sides:

$9y-9y+20=19y-9y\\\\20=10y$

Isolate the variable. Divide both sides by 10:

$\frac{20}{10} =\frac{10y}{10} \\\\y=2$

The value of y is 2. Insert this value into each line segment value and solve:

$PQ=8(2)+6\\\\PQ=16+6\\\\PQ=22$

$QR=(2)+5\\\\QR=7$

$PR=19(2)-9\\\\PR=38-9\\\\PR=29$

:Done

You can check by using:

$PQ+QR=PR\\\\22+7=29$

This statement is true, so the values are correct.

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3 years ago

The area of a rectangle is 27 ft2 , and the length of the rectangle is 3 ft less than double the width. find the dimensions of t

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w(2w-3)=27
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3 years ago

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Volgvan

Answer:

4.2

Step-by-step explanation:

.7*6

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3 years ago