Answer:
3x= 2y +6
and when we put y = 0
then 3x = 6
x = 6/3
x =2
SECOND one , when we put x = 0
0= 2y +6
-6 = 2y
-6/2= y
-3 = y
Answer:
3 ln(x − 1) − 3/(x − 1) + C
Step-by-step explanation:
∫ 3x / (x − 1)² dx
3 ∫ x / (x − 1)² dx
If u = x − 1, then x = u + 1, and du = dx.
3 ∫ (u + 1) / u² du
3 ∫ (1/u + 1/u²) du
3 (ln u − 1/u + C)
3 ln u − 3/u + C
Substitute back:
3 ln(x − 1) − 3/(x − 1) + C
Answer:
First option
Step-by-step explanation:
You answer is A. You have to substitute the values of x and y into the equation.
(3*1)= 4-1
4-(2*1)=2
(4,1)
(x,y)
