For this case we have the following functions:
h (x) = 2x - 5
t (x) = 6x + 4
Part A: (h + t) (x)
(h + t) (x) = h (x) + t (x)
(h + t) (x) = (2x - 5) + (6x + 4)
(h + t) (x) = 8x - 1
Part B: (h ⋅ t) (x)
(h ⋅ t) (x) = h (x) * t (x)
(h ⋅ t) (x) = (2x - 5) * (6x + 4)
(h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
(h ⋅ t) (x) = 12x ^ 2 - 22x - 20
Part C: h [t (x)]
h [t (x)] = 2 (6x + 4) - 5
h [t (x)] = 12x + 8 - 5
h [t (x)] = 12x + 3
Answer:
The value of the given expression is
Step by step Explanation:
Given that 
To find the value of 
Let us find the value of the expression :
( by using the formula 
here A=2A)
(using 
here A=2A)
(using 
here A=2A)
( using 
here A=2A )
(since tanA=a given )
Therefore
Using the pairs (1,32) and (2,64) the rate of speed is (64-32 / 2-1 = 32 feet per second.
To find the rate of decent you would multiply the rate by time:
The equation is y = 32x
B. Replace x with 15 and solve for y:
Y = 32(15)
Y = 480
The rate of speed is 480 feet per second.
Answer:
Yes, F is a continuous function of r
Step-by-step explanation:
We are given that
When r<R
Where M=Mass of the earth
R=Radius of earth
G=Gravitational constant
We have to find the function is continuous of r or not.
LHL
RHL
When a function is continuous at x=a
Then, LHL=RHL=f(a)
RHL==LHL=F(R)
Hence, the function is continuous of r.
