Based on the width of the aluminum sheets and the angle of the edges, the depth that allows maximum cross-sectional area is 4 inches.
<h3>How much can the maximum cross-sectional area?</h3>
Assuming that the depth is x, the area would be:
= x (16 - 2x)
= 16x - 2x²
The maximum of the parabola is:
x = -b / 2a
= - 16 / (2 x -2)
= -16 / -4
= 4 inches
Find out more on using a parabola to solve for height at brainly.com/question/2274171
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1 1/11 or 12/11 as an improper fraction.
The answer is D
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The answer is -7. Do you actually wanna know how to solve it?
The first/selected graph matches g(x)=0.2*2^x