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azamat
3 years ago
15

You put $500 into an account and left it alone for three years earning simple interest. At the end of three years, you withdrew

$650. What interest rate did you earn? (I = PRT)
Mathematics
1 answer:
OLga [1]3 years ago
5 0

Answer:

that would mean 15$ a year

1.25$ a month

Step-by-step explanation:

hope it helped

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tom is 57 years old. Tom has a son ,james. In 3 years tom will be twice as old as james. How old is james
Serhud [2]

Answer: 27

Step-by-step explanation:

Tom is 57 now. In 3 years he will be 60, but also twice as old as his son. 1/2 of 60 is 30. 30 minus the 3 years that hasn’t happened yet equals 27.

3 0
3 years ago
Read 2 more answers
A gasoline tank for a certain car is designed to hold 14.0 gal of gas. Suppose that the variable x = actual capacity of a random
MariettaO [177]

Answer:

A gasoline tank for a certain car is designed to hold 14.0 gal of gas.

\mu = 14

\sigma = 0.2

a)What is the probability that a randomly selected tank will hold at most 13.7 gal?

We are supposed to find P(x \leq 13.7)

z=\frac{x-\mu}{\sigma}

z=\frac{13.7-14}{0.2}

z=-1.5

Refer the z table for p value

p value = 0.0668

So, P(x \leq 13.7)= 0.0668

The probability that a randomly selected tank will hold at most 13.7 gal is  0.0668

b)What is the probability that a randomly selected tank will hold between 13.4 and 14.3 gal?

We are supposed to find P(13.4

z=\frac{x-\mu}{\sigma}

z=\frac{13.4-14}{0.2}

z=-3

P(x<13.4)=P(z<-3)= 0.0013

z=\frac{x-\mu}{\sigma}

z=\frac{14.3-14}{0.2}

z=1.5

P(x<14.3)= 0.9332

P(13.4

The probability that a randomly selected tank will hold between 13.4 and 14.3 gal is 0.9319

(c) If two such tanks are independently selected, what is the probability that both hold at most 14 gal?

We are supposed to find P(x \leq 14)

z=\frac{x-\mu}{\sigma}

z=\frac{14-14}{0.2}

z=0

Refer the z table for p value

p value = 0.5

So, P(x \leq 14)= 0.5

Two such tanks are independently selected, the probability that both hold at most 14 gal = 0.5 * 0.5 = 0.25

Hence If two such tanks are independently selected, the probability that both hold at most 14 gal is 0.25

3 0
2 years ago
Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
Alik [6]

Answer:

P(X

And for this case we can use the cumulative distribution function given by:

P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b

And using this formula we have this:

P(X

Then we can conclude that the probability that your bid will be accepted would be 0.41

Step-by-step explanation:

Let X the random variable of interest "the bid offered" and we know that the distribution for this random variable is given by:

X \sim Unif( a= 10100, b =14700)

If your offer is accepted is because your bid is higher than the others. And we want to find the following probability:

P(X

And for this case we can use the cumulative distribution function given by:

P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b

And using this formula we have this:

P(X

Then we can conclude that the probability that your bid will be accepted would be 0.41

8 0
2 years ago
A: 2x - 3y = 6
madam [21]
It’s A and B or C and D
4 0
2 years ago
PLZ HELP ASAP FEATURES OF A CIRCLE FROM ITS EXPANDED EQUATION LAST ONE
pantera1 [17]
We have the following equation:
 x2 + y2 + 6y - 72 = 0
 Rewriting we have:
 x2 + y2 + 6y = 72
 Complete squares we have:
 x2 + y2 + 6y + (6/2) ^ 2 = 72 + (6/2) ^ 2
 x2 + y2 + 6y + (3) ^ 2 = 72 + (3) ^ 2
 x2 + y2 + 6y + 9 = 72 + 9
 x2 + (y + 3) 2 = 81
 So, the center is:
 (0, -3)
 The radio is:
 r = 9
 Answer:
 
(0, -3)
 
r = 9
5 0
2 years ago
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