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3 years ago

What’s the answer to3/4 + 3/8 - 5/8

Mathematics

1 answer:

evablogger [386]3 years ago

8 0

Answer:

Step-by-step explanation:

Answer 0.5

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A worm moves forward 3/8 inch every 5 minutes for 1 hour 25 minutes. How fast does the worm move in this time?

Alina [70]

Multiply <span>3/8 inch by 75 and divide by 5</span>

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3 years ago

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Solve for m and n<br> I been stuck on this question for an hour

Crazy boy [7]

Answer:

m = 10 , n = 5 $\sqrt{2}$

Step-by-step explanation:

using the cosine and tangent ratio in the right triangle and the exact values

cos45° = $\frac{1}{\sqrt{2} }$ and tan45° = 1 , then

cos45° = $\frac{adjacent}{hypotenuse}$ = $\frac{5\sqrt{2} }{m}$ = $\frac{1}{\sqrt{2} }$ ( cross- multiply )

m = 5 $\sqrt{2}$ × $\sqrt{2}$ = 5 × 2 = 10

-----------------------------------------

tan45° = $\frac{opposite}{adjacent}$ = $\frac{n}{5\sqrt{2} }$ = 1 , then

n = 5 $\sqrt{2}$

3 0

1 year ago

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

4 0

3 years ago

Seattle, Washington is known for being very rainy. One day last month, 8 inches of rain fell in 1 1/2 hours. What is the rate of

Leno4ka [110]

Answer:

0.44ft/hr

Step-by-step explanation:

Given parameters:

Quantity of rainfall = 8inches

1ft = 12inches

so;

$\frac{8}{12}$ = 0.67ft

Time = $\frac{3}{2}$ hr

Unknown:

Rate of rainfall expressed in ft/hr = ?

Solution:

The rate of the rainfall is given as;

Rate = $\frac{Quantity}{time}$

Rate = $\frac{0.67ft}{\frac{3}{2} }$ = 0.44ft/hr

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2 years ago

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For each of the figures, write an absolute value equation to satisfy the given solution set.

Snowcat [4.5K]

|x -4| -4 = 0
is one such equation.

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