Explain how complex fractions can be used to solve problems involving ratios?

1 answer:

8 0

Complex fractions are numbers in which the numerator and the denominator are both fractions. in this case, to solve the ratio, we can multiply the numerator fraction by the reciprocal of the denominator fraction. Another way is to solve the fraction separately and then divide eventually.

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Triangle ABC is dilated to produce triangle A'B'C' with scale factor 3/4. which describes the relationship between the two trian

Nadya [2.5K]

Answer:

ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.

Step-by-step explanation:

It is given that the triangle ABC is dilated to produce triangle A'B'C' with scale factor 3/4.

If a figure is dilated then preimage and image are similar.

If scale factor is between 0 to 1, then preimage is reduction of image.

If scale factor is more that 1, then preimage is enlargement of image.

If scale factor is 1, then preimage is congruent to the image.

We know that

$\frac{3}{4}=0.75$

So,

$0$

Therefore, the ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.

6 0

3 years ago

Find the equation of a parabola with a vertical axis and its vertex at the origin and passing through the point (-2, 3)

vredina [299]

a vertical axis, I assume it means a vertical axis of symmetry, thus it'd be a vertical parabola, like the one in the picture below.

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \qquad \leftarrow vertical\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=0\\ k=0 \end{cases}\implies y=a(x-0)^2+0 \\\\\\ \textit{we also know that } \begin{cases} x=-2\\ y=3 \end{cases}\implies 3=a(-2-0)^2+0\implies 3=4a \\\\\\ \cfrac{3}{4}=a~\hspace{10em}y=\cfrac{3}{4}(x-0)^2+0\implies \boxed{y=\cfrac{3}{4}x^2}$