An object is launched straight into the air. The projectile motion of the object can be modeled using h(t) = 96t – 16t2, where t is the time since launch and h(t) is the height in feet of the projectile after time t in seconds. When will the object be 144 feet in the air? When will the object hit the ground?
2 answers:
Answer:
The object will be 144 feet in the air at t= 3 seconds At t= 6 seconds, the object will hit the ground. Step-by-step explanation:
We have been the model
Here. t is the time since launch and h(t) is the height in feet of the projectile after time t in seconds.
For the height of the object to be 144 feet, we have
Therefore, after 3 seconds the object will be 144 feet in the air.
Now, when the object hits the ground then the height should be zero.
Hence, at t= 6 seconds, the object will hit the ground.
Answer to Q1 is it will be 144 feet high in the air : after 3.0 seconds Answer to Q2 is it will hit the groundat about: after 6.0 seconds
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