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yanalaym [24]
1 year ago
15

Consider the given density curve.

Mathematics
1 answer:
Gemiola [76]1 year ago
4 0

Answer:

11 is best answer for it ....,..........

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The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?
s344n2d4d5 [400]
{k^2 + 2k + 1 = 25, k^2 + 2k + 1 = 64}
{k^2 + 2k - 24 = 0, k^2 + 2k - 63 = 0}
{(k - 4)(k + 6) = 0, (k - 7)(k + 9) = 0}
{k = -6, 4, -9, 7)
Therefore, range = {-9, -6, 4, 7)
3 0
3 years ago
Solve for x: [x - 2 + 10 = 12
Monica [59]

Answer:x-2+10=12

We move all terms to the left:

x-2+10-(12)=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

Step-by-step explanation:

5 0
3 years ago
Which graph shows the solution to the equation below? log Subscript 3 Baseline (x + 3) = log Subscript 0.3 (x minus 1) On a coor
Effectus [21]

Answer:

On a coordinate plane, 2 curves intersect at (1, 1). One curve curves up and to the right from quadrant 3 into quadrant 1. The other curve curves down from quadrant 1 into quadrant 4

Step-by-step explanation:

The first function is given as:

log_3(x+3)

The second function is given as:

log_{0.3}(x-1)

First we graph both the functions.

We can see that one curves up and to the right from quadrant 3 into quadrant 1. This curve is of  log_3(x+3)

The other curve curves down from quadrant 1 into quadrant 3

Both curves interest almost at (1,1)

See the graph attached below

Blue line represents first function

Green line represents second function

The solution lies on the Red line.

8 0
3 years ago
Read 2 more answers
9 1/5 into an improper fraction
vaieri [72.5K]

Answer:

46/5 hope it helps!

Step-by-step explanation:

9x5= 45

45+1= 46

46/5

7 0
3 years ago
Which equation has the same soultions as x^2+6×-7=0
blagie [28]
x^2+6x-7=0 \\   a=1 \\ b= 6 \\ c=-7 \\ \\  \boxed{\boxed{\Delta=b^2-4ac}} \\ \\ \Delta=6^2-4*1*(-7) \\ \Delta=36-(-28) \\ \Delta=64 \\ \Delta\ \textgreater \ 0 \Rightarrow \text{we have 2 solutions :} X_1 \ and X_2 \\ \\ \boxed{X_1= \frac{-b- \sqrt{\Delta} }{2a} } \Rightarrow X_1= \frac{-6-8}{2}=-7 \\ \\ \boxed{X_2= \frac{-b+ \sqrt{\Delta} }{2a} } \Rightarrow X_2= \frac{-6+8}{2} =1
4 0
2 years ago
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