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guajiro [1.7K]
3 years ago
14

The debits and credits for four related entries for a sale of $15,000, terms 1/10, n/30, are presented in the following T accoun

ts. Cash (5) 13,860 Accounts Receivable (1) 14,850 (3) 990 (5) 13,860 Merchandise Inventory (4) 575 (2) 8,800 Estimated Returns Inventory (4) 575 Customer Refunds Payable (3) 990 Sales (1) 14,850 Cost of Merchandise Sold (2) 8,800 Describe each transaction. 1. Sold merchandise on account. 2. Recorded the cost of the merchandise sold and reduced the merchandise inventory account. 3. 4. 5. Check My Work5 more Check My Work uses remaining.
Business
1 answer:
kupik [55]3 years ago
4 0

please finThe debits and credits for four related entries for a sale of $15,000, terms 1/10, n/30, are presented in the following T accounts. EXPLANATIONS for these accounts are given below in an attachment

                                           

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On August 2, Jun Co. receives a $7,000, 90-day, 11.5% note from customer Ryan Albany as payment on his $7,000 account. Prepare J
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Answer:

Oct 31

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Cr Notes receivable—R. Albany $7,000

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Explanation:

Preparation of Jun's journal entry assuming the note is honored by the customer on October 31, of that same year

Oct 31

Dr Cash $7,201

($7,000+$201)

Cr Notes receivable—R. Albany $7,000

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3 years ago
__ occurs when a government demands partial transfer of ownership and management responsibility and imposes regulations to ensur
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Answer: Option C : Domestication

Explanation: Domestic policy or domestication are administrative decisions that are directly related to all activities and issues within a nation's physical borders. It's a more critical way of looking at foreign policy with a difference.

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3 years ago
Peterson's Antiquities currently has a 31 day cash cycle. Assume the firm changes its operations such that it decreases its rece
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Answer: 30 days

Explanation: Cash cycle refers to the amount of time it takes for a business from paying cash to its suppliers for raw materials and receiving cash from its customers fro the sales made.

Hence from the above we can say that :-

decrease in inventory will decrease the cycle.

Decrease in receivables will decrease the cycle.

decrease in payables will increase the cycle.

Thus,

cash cycle =  31 days - 2 days + 4 days - 3 days

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4 years ago
Suppose the world population today is 7 billion, and suppose this population grows at a constant rate of 3% per year from now on
oksano4ka [1.4K]

Answer:

a) P(t=100) = 7 e^{0.03*100}=140.599 billion

b) P(t=0) = 7 e^{0.03*0}=7 billion

P(t=1) = 7 e^{0.03*1}=7.21 billion

P(t=2) = 7 e^{0.03*2}=7.43 billion

P(t=10) = 7 e^{0.03*10}=9.45 billion

P(t=25) = 7 e^{0.03*25}=14.82 billion

P(t=50) = 7 e^{0.03*50}=31.37 billion

c) Figure attached

d) Figure attached

Explanation:

The proportional model on this case would be given by:

\frac{dP}{dt} = kP

Where P is the population size, t the time on years and k a constant.

We can reorder this expression like this:

\frac{dP}{P} = k dt

If we integrate both sides we got:

ln|P| = kt + C

And using exponentials on both sides we got:

P(t) = e^{kt} e^C = P_o e^{kt}

Where P_o=7 billion  represent the initial amount for the starting year t=0.

The rate on this case is given r =3\% = 0.03, so then our model would be given by:

P(t) = 7 e^{0.03t}

Part a

For this case we just need to replace t=100 and we got:

P(t=100) = 7 e^{0.03*100}=140.599 billion

Part b

For this case we have the following:

P(t=0) = 7 e^{0.03*0}=7 billion

P(t=1) = 7 e^{0.03*1}=7.21 billion

P(t=2) = 7 e^{0.03*2}=7.43 billion

P(t=10) = 7 e^{0.03*10}=9.45 billion

P(t=25) = 7 e^{0.03*25}=14.82 billion

P(t=50) = 7 e^{0.03*50}=31.37 billion

Part c

The graph is on the first figure attached.

Part d

If we take a log-log scale we have the following values

We need to exclude the point t=0 since the natural log for 0 is not defined.

ln 1 =0 , ln 2= 0.693, ln 10=2.30, ln 25 =3.22, ln 50= 3.91

The result would be the figure 2 attached. And we see a better result for the graph.

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Answer:

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Explanation:

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