1)Calculate the product:
21a + 10a - 3a
2)Collect like terms:
28a
Answer:
28a
Answer:
159 m
Step-by-step explanation:
From the information given:
It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.
Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.
Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.
We are to find, the magnitude of the ostrich's eastward component.
i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.
Using the Pythagoras rule:
ES² = OE² + OS²
226² = OE² + 161²
226² - 161² = OE²
OE² = 226² - 161²
OE² = 51076 - 25921
OE² = 51076 - 25921
OE² = 25155

OE = 158.60 m
OE ≅ 159 m
Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.
Answer:
Train A = 299 tons Train B = 50 tons
Step-by-step explanation:
Train A = x
Train B = y
x+y = 349
x= y +249
Plug in one equation into another
y+249+y= 349
Simplify
2y+249=349
Subtract 249 from both sides
2y=100
Divide both sides by 2
y=50
Plug it into the x equation to solve for x
x+50=349
-50 from both sides
x=299
Answer:
2.57 x 10^(-5)
Step-by-step explanation:
you have to move the comma sign in front of the first number considering 0 as a non-number.
The equation is given as

<h3>The Amplitude </h3>
The Amplitude can be calculated as

<h3>The Vertical Shift</h3>
The vertical shift is the average difference between the maximum and minimum.

For b value
The Time Period will be twice the distance between max and min.

<h3>The Period</h3>
The period is calculated as

The equation is given as

Learn more on time period and amplitude here;
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