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Vlad [161]
2 years ago
12

I need help please.

Mathematics
1 answer:
quester [9]2 years ago
6 0

Answer:

?  = 22y^2

Step-by-step explanation:

Ask yourself, what times 20y will get me 40y^3?

The answer to this would be 2y^2.

When you multiply something to the denominator, you also have to do so to the numerator. Therefore, you are required to multiply 2y^2 to the 11 to get your '?' value.

11 x 2y^2 = 22y^2

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+Given: AB ≅ AD and AB≅ AD AC≅ BD. Prove △BAE≅△DAE.
Daniel [21]

Answer:

Step-by-step explanation:

Given:

AB ≅ AD

AC ⊥ BD

To Prove:

ΔBAE ≅ ΔDAE      

                 Statements                        Reasons

1). AB ≅ AD and AC ⊥ BD             1). Given

2). AE ≅ AE                                   2). Reflexive property

3). ΔBAE ≅ ΔDAE                         3). HL postulate of congruence

8 0
3 years ago
In a couple of sentences and in your own words describe in what ways horizontal, vertical, and oblique asymptotes can be identif
drek231 [11]
A horizontal asymptote is one in which y has a limit as x approaches positive or negative infinite. It is usually due to both the denominator and the numerator having the same highest degree term, and the coefficient created by their proportion serves as the asymptote. For example, (2x^2 + 1) / (3x^2) would have a horizontal asymptote of 2/3

A vertical asymptote is an x value at which y approaches infinite. One example includes when the denominator of the function approaches zero at a certain point. For example, (x^2 + 3) / (x + 1) has a vertical asymptote at x=-1, since the denominator approaches zero as x approaches this point. 

For an oblique asymptote, y generally takes the form of a linear function as x approaches infinite. This is the case when the highest term in numerator is one degree higher than the highest degree term in the denominator. 

Examples include (5x^2 + 2) over 2x, where the oblique asymptote is (5/2)x, and even the linear function 2x+3 has an oblique asymptote of 2x
5 0
3 years ago
PLEASE ANSWER QUICK! I REALLY NEED HELP!
Katarina [22]

Answer:

a) Angle 1 = Value in degree = 95°

b)Angle 2 = Value in degree = 77°

c) Angle 3 = Value in degree = 85°

d) Angle 4 = Value in degree = 103°

Step-by-step explanation:

We use circle theorems to solve for this above question.

a) Angle 1 = Value in degree = 95°

Inscribed Angle is 1/2 of an Intercepted Arc

From the diagram, Angle 1 intersects at Arc B and Arc C

This means Angle 1 = (B + C)/ 2 =

Arc B = 100°

Arc C = 90°

Angle 1. = (100° + 90°)/ 2 = 190/ 2 = 95°

b)Angle 2 = Value in degree = 77°

From the diagram, Angle 2 intersects at Arc C and Arc D

Inscribed Angle is 1/2 of an Intercepted Arc

This means Angle 1 = (C+ D)/ 2

C = 90°

D = 64°

Angle 1. = (90° + 64°)/ 2 = 154/ 2 = 77°

c) Angle 3 = Value in degree = 85°

From the diagram, we can see that Angle 1 is opposite Angle 3, hence,

Opposite angles are supplementary which means their addition = 180°

Mathematically:.Angle 1 + Angle 3 = 180°

Angle 1 = 95°

95° + Angle 3 = 180°

Angle 3 = 180° - 95° = 85°

d) Angle 4 = Value in degree = 103°

From the diagram, we can see that Angle 2 is opposite Angle 4,

Hence,

Opposite angles are supplementary which means their addition = 180°

Mathematically:.Angle 2 + Angle 4 = 180°

Angle 2 = 77°

77° + Angle 3 = 180°

Angle 4 = 180° - 77° = 103°

4 0
3 years ago
A. zero<br> B. negative<br> C. positive
Alja [10]
The answer is zero sorry if I am wrong
7 0
3 years ago
Read 2 more answers
Write the slope-intercept form of the equation of the line.<br> slope = 1, y, int = -2
choli [55]

Answer:

y = x - 2

General Formulas and Concepts:

<u>Algebra I</u>

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Slope <em>m</em> = 1

y-intercept <em>b</em> = -2

<u>Step 2: Write linear function</u>

y = x - 2

8 0
3 years ago
Read 2 more answers
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