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harina [27]
3 years ago
12

Solve the following system of equations for a and for b:

Mathematics
1 answer:
viktelen [127]3 years ago
5 0

Answer:

a=3\\b=1

Step-by-step explanation:

9a+3b=30\\8a+4b=28

Let's solve the second equation for a to later on replace it in the first equation.

8a+4b=28\\8a=28-4b\\a=\frac{28-4b}{8}

Now plug this into the first equation.

9a+3b=30\\9(\frac{28-4b}{8})+3b=30

Distribute the 9

(\frac{252-36b}{8}) +3b=30

Break down the fraction.

\frac{252}{8}-\frac{36b}{8}+3b=30

Simplify.

\frac{63}{2}-\frac{9}{2}b+3b=30

Subtract \frac{63}{2}

-\frac{9}{2}b+3b=30-\frac{63}{2}

Combine like terms.

\frac{-9+2*3}{2}b=\frac{30*2-63}{2}

\frac{-9+6}{2}b=\frac{60-63}{2}

\frac{-3}{2}b=\frac{-3}{2}

Muliply by the reciprocal or inverted fraction next to b.

(-\frac{2}{3})(-\frac{3}{2}) b=-\frac{3}{2}(-\frac{2}{3})

b=1

Now plug this value into any of the equations to find the value of a.

8a+4b=28\\8a+4(1)=28\\8a+4=28\\8a=28-4\\8a=24\\a=\frac{24}{8}\\ a=3

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