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Artist 52 [7]
3 years ago
12

Suppose total benefits and total costs are given by b(y) = 100y − 8y2 and c(y) = 10y2. what is the maximum level of net benefits

(rounded to the nearest whole number)?
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
3 0
Whenever you face the problem that deals with maxima or minima you should keep in mind that minima/maxima of a function is always a point where it's derivative is equal to zero.
To solve your problem we first need to find an equation of net benefits. Net benefits are expressed as a difference between total benefits and total cost. We can denote this function with B(y).

B(y)=b-c
B(y)=100y-18y²

Now that we have a net benefits function we need find it's derivate with respect to y.

\frac{dB(y)}{dy} =100-36y

Now we must find at which point this function is equal to zero.

0=100-36y
36y=100
y=2.8

Now that we know at which point our function reaches maxima we just plug that number back into our equation for net benefits and we get our answer.

B(2.8)=100(2.8)-18(2.8)²=138.88≈139.

One thing that always helps is to have your function graphed. It will give you a good insight into how your function behaves and allow you to identify minima/maxima points.


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Let d=discriminant.  The the rule is:

d>0, there are two real solutions

d=0, there is one real solution

d<0, there is no real solutions (but there are two imaginary solutions)

So if it is positive, there are two real solutions.
3 0
3 years ago
Which calculation will ALWAYS give a result greater than 1? A.8/9 × a number less than 1 B.1 2/5 − a fraction less than 25 C. 7
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Answer: B.1 2/5 − a fraction less than 2/5

Step-by-step explanation:

Question was not formatted properly and in the proper format, the above is the answer.

1²/₅ - ²/₅ = 1

Any number therefore that is lower than ²/₅ will when subtracted from 1²/₅ give an answer greater than 1 because when ²/₅  was subtracted from  1²/₅, it gave 1 as an answer.

7 0
3 years ago
In 1990 the average family income was about $ 39 , 000 , and in 2010 it was about $ 70 , 768 . Let x = 0 represent 1990, x = 1 r
iren2701 [21]

Answer:

<em />f(x) = 1588.4x + 39000<em />

f(15) = 62826

Step-by-step explanation:

Given

In 1990; Income= $39000

In 2010; Income= $70768

Solving (a): An equation in form of f(x) = ax + b

First, we need to determine the slope, a

a = \frac{y_2 - y_1}{x_2 - x_1}

Taking y as income and x as year index.

When x = 0; y = 39000

When x = 20; y = 70768

Substitute these values in the above formula

a = \frac{70768 - 39000}{20 - 0}

a = \frac{31768}{20}

a = 1588.4

Next, is to determine the formula using:

y - y_1 = a(x - x_1)

<em>Considering :When x = 0; y = 39000, we have</em>

<em />y - 39000 = 1588.4(x - 0)<em />

<em />y - 39000 = 1588.4x<em />

<em>Make y the subject of formula</em>

<em />y = 1588.4x + 39000<em />

<em />

<em>Express y as a function of x</em>

<em />f(x) = 1588.4x + 39000<em />

Solving (b): Income in 2005

<em>In 2005, x = 15</em>

So:

f(x) = 1588.4x + 39000 becomes

f(15) = 1588.4 * 15 + 39000

f(15) = 62826

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