AB has endpoints at -2 and 12. What is the coordinate of its midpoint?
1 answer:
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Y = - 4x^2 - 3x + 3 This thing is complex with fractions. I have to work it out.
y = -4(x^2 + 3/4 x) + 3
y = -4(x^2 + 3/4 x + (3/8)^2 ) + 3
y = -4(x + 3/8)^2 +3 + 4*(9/64)
y = -4(x + 3/8)^2 + 3 + 9/16
y = -4(x + 3/8)^2 + 3 9/16 Equation in Vertex form. <<<<< answer
y = -4(x + 0.385) + 3.5625 Equation in Vertex form. <<<< answer
One is in decimal form. One in fraction form.
the vertex (-3/8, 3 9/16) or alternately
the vertex (-0.375,3.5625)
You might want the graph to confirm my answer.
y = -4(x^2 + 3/4 x) + 3
y = -4(x^2 + 3/4 x + (3/8)^2 ) + 3
y = -4(x + 3/8)^2 +3 + 4*(9/64)
y = -4(x + 3/8)^2 + 3 + 9/16
y = -4(x + 3/8)^2 + 3 9/16 Equation in Vertex form. <<<<< answer
y = -4(x + 0.385) + 3.5625 Equation in Vertex form. <<<< answer
One is in decimal form. One in fraction form.
the vertex (-3/8, 3 9/16) or alternately
the vertex (-0.375,3.5625)
You might want the graph to confirm my answer.
Answer:
<h2>2(x - 5)(x + 3)</h2>Step-by-step explanation: