Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
Answer:
0.2y+10
Step-by-step explanation:
0.9 is the answer hope it helps.
Answer:
Step-by-step explanation:
multiply x as a negative.
Example:
f(x) = 3x + 1
f(-x) = -1(3x) + 1
f(-x) = -3x + 1
Answer:
The line has a slope of 0. The equation would be y=-5.
Step-by-step explanation:
There are true statements.
