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Debora [2.8K]
3 years ago
11

Solve the compound inequality n-4 > 5 AND 2 > n + 3

Mathematics
1 answer:
Papessa [141]3 years ago
5 0
Get n by itself in both inequalities

(This program doesn't allow for regular less than or greater than signs, so for the purposes of this problem I will be using less than or equal to (≤) and greater than or equal to (≥) signs)

Inequality 1:
n-4   \geq 5 \\ n \geq 9

Inequality 2:
2 \geq n+3 \\ -1 \geq n

Now that you have both of the n's by themselves, you can put the two inequalities together, like this
-1 \geq n \geq 9

Just keep in mind that these are supposed to be regular less than signs
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Peter Johnson, the CFO of Homer Industries, Inc is trying to determine the Weighted Cost of Capital (WACC) based on two differen
Rzqust [24]

Answer:

Scenario 1 has WACC of 7.93%

Scenario 2 has WACC of 10.33%

Step-by-step explanation:

WACC=Ke*E/V+Kp*P/V+Kd(after tax)*D/V

Ke is the cost of equity =13%

Kp is the cost of preferred stock=10%

Kd(after tax) is the cost of debt of 8% adjusted for tax as below:

Kd(after tax )=Kd(before tax)*(1-t)

t is the tax rate of 30% or 0.3

Kd(after tax)=8%*(1-0.3)=5.60%

E is equity value,which is $1.8 million under scenario 1 and $3.8 under scenario 2

P is the value of preferred stock which is $1.2 million and $2.2 million respectively

D is the value of debt which is $5 million and $2 million

V=total value of capital structure=$8 million in both cases.

Scenario 1 WACC

WACC=13%*1.8/8+10%*1.2/8+5.6%*5/8=7.93%

Scenario 2 WACC

WACC=13%*3.8/8+10%*2.2/8+5.6%*2/8=10.33%

7 0
3 years ago
What 80/99 equals what percent
Hitman42 [59]
If you divide 80 by 99, you 'll get about 80/99 = 0.808; So, to get in in percentage, which means a fraction over 100, you just multiply it by 100: 0.808*100= 80.8; So 80/99=80.8%; Hope this Helps! :)
4 0
4 years ago
Read 2 more answers
What is the product? Express the answer in lowest terms. Two-thirds times six-elevenths
ehidna [41]

Answer:

\frac{4}{11} or four elevenths

\frac{2}{3} × \frac{6}{11} = \frac{12}{33}

Simplified it equals:

\frac{4}{11}

<u>Hope this helps and have a nice day!</u>

3 0
4 years ago
Find the first four iterates of the function f(z)=z^2-2-2i with an initial value of z0=2+i
olga nikolaevna [1]

Obtain the next iterate by plugging the previous iterate into the function.

First iterate:

z_0=2+i\implies z_1=f(z_0)=(2+i)^2-2-2i=1+2i

Second iterate:

z_2=f(z_1)=(1+2i)^2-2-2i=-5+2i

Third iterate:

z_3=f(z_2)=(-5+2i)^2-2-2i=19-22i

Fourth iterate:

z_4=f(z_3)=(19-22i)^2-2-2i=-125-838i

4 0
3 years ago
Evaluate and simplify the<br> expression when a=2 and b=4.<br> 4a + 2b2 - 2(a – 3b) = [?]
ahrayia [7]

Answer:

92

Step-by-step explanation:

let's start off by plugging 2 for every a in the equation and 4 for every b.

4a+2b^2-2(a-3b)=?

4(2)+2(4)^2-2(2-3(4))=?

8+8^2-2(2-12)=?

8+64-2(-10)=?

8+64+20=?

?=92

5 0
4 years ago
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