HELPPPPPPPP ASAPPPPP PLSSSS

All sides of a square and a pentagon are 9 inches long. Are their perimeters the same? Explain

EastWind [94]

No they wouldn't be the same because, the perimeter is adding all sides.

The square has 4 sides so you would add 9, four times.

9 + 9 + 9 + 9 = 36

And a pentagon has 5 sides so you would add 9, five times.

9 + 9 + 9 + 9 + 9 = 45

So, they are not the same.

Hope this helps. :)

4 0

3 years ago

Pls help I dont know how to do this

german

Answer:

1. CE = 63
2. x = 16

Step-by-step explanation:

Use proportions to solve.

Corresponding sides have same ratio.

Question 1

DE/EG = CE/EF

(6x + 3)/17 = (8x - 1)/21
21(6x + 3) = 17(8x - 1)
126x + 63 = 136x - 17
10x = 80
x = 8

CE = 8*8 - 1
CE = 63

Question 2

KM/MD = KZ/ZH

(x + 8)/21 = 32/28
x + 8 = 21*8/7
x + 8 = 24
x = 24 - 8
x = 16

5 0

2 years ago

Which set of ordered pairs contains only points that are on the graph of the function y=12-3×?

irina [24]

Y= 12 -3x so if you take x as 0 y=12 x=1 y=9 x=2 y=6

(0, 12) (1,9), (2,6) are on the graph

8 0

3 years ago

3. The adult men of the Dinaric Alps have the highest average height of all regions. The

ahrayia [7]

Using the normal distribution, it is found that:

3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

4 - a) The 25th percentile for the math scores was of 71.6 inches.

4 - b) The 75th percentile for the math scores was of 78.4 inches.

<h3>Normal Probability Distribution </h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

Question 3:

The mean is of 73 inches, hence $\mu = 73$ .

The standard deviation is of 3 inches, hence $\sigma = 3$ .

Item a:

The 40th percentile is X when Z has a p-value of 0.4, so X when Z = -0.253.

$Z = \frac{X - \mu}{\sigma}$

$-0.253 = \frac{X - 73}{3}$

$X - 73 = -0.253(3)$

$X = 72.2$

The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

Item b:

The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so X when Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 73}{3}$

$X - 73 = 1.28(3)$

$X = 76.84$

The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

Question 4:

The mean score is of 75, hence $\mu = 75$ .

The standard deviation is of 5, hence $\sigma = 5$ .

Item a:

The 25th percentile is X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 75}{5}$

$X - 75 = -0.675(5)$

$X = 71.6$

The 25th percentile for the math scores was of 71.6 inches.

Item b:

The 75th percentile is X when Z has a p-value of 0.25, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 75}{5}$

$X - 75 = 0.675(5)$

$X = 78.4$

The 75th percentile for the math scores was of 78.4 inches.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

5 0

2 years ago

Can someone help pls

Arlecino [84]

Answer:

I think it may be D

Step-by-step explanation:

A coefficient is the number being multiplied by the variable. A variable is a letter that holds an number like w x 7=? W=6. And a constant is the number by itself. In this expression 5000 is the constant 20 is the coefficient and teh variable is w so I think it is D

5 0

2 years ago