Alright so if I do remember my math correctly, this is how it goes:
- y = -x^2 + x + 3
- x = -b/2a
- x = -1/2(-1)
- x = -1/-2, which = (1/2)
Not quite sure if this was correct, but if it was, hope this helps and you're welcome! :)
Answer:
A
Step-by-step explanation:
X<Y means x is less than y-5 and you get A.
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
2x+3-5.32=68.82
2x= 71.14
x=35.57
each sneaker costs $35.57