Which of these choices is the length of the leg of a 45-45-90 triangle with a hypotenuse of 20?

Mathematics

2 answers:

Marta_Voda [28]3 years ago

8 0

Answer: The correct choice is 10√2 units.

Step-by-step explanation: We are given to select the correct choice that gives the length of the leg of a 45-45-90 triangle with a hypotenuse of 20.

Since the given triangle is an isosceles right-angled triangle, so let x units be the length of each of the legs.

Using the Pythagoras theorem, we get

$x^2+x^2=20^2\\\\\Rightarrow 2x^2=400\\\\\Rightarrow x^2=\dfrac{400}{2}\\\\\Rightarrow x^2=200\\\\\Rightarrow x=\pm\sqrt{2\times100}\\\\\Rightarrow x=\pm10\sqrt2.$

Since x is the length of the leg of the given triangle, so we get

x = 10√2 units.

Thus, the correct choice is 10√2 units.

Nuetrik [128]3 years ago

7 0

The answer would be b.20

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. Shanice is making a garden. The area of the garden is 24 ft2. Use the following shape and information to find the base (6−4) a

crimeas [40]

Answer:

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Step-by-step explanation:

The area of the garden is, A = 24 ft².

The base height of the garden are:

base (b) = 6x - 4

height (h) = x + 3

Compute the value of x as follows:

$A=\frac{1}{2}\times b \times h\\\\24=\frac{1}{2}\times (6x-4) \times (x+3)\\\\48=6x^{2}+18x-4x-12\\\\6x^{2}+14x-60=0\\\\3x^{2}+7x-30=0\\$

The last equation is a quadratic equation.

Compute the roots of the quadratic equation as follows:

$x = \frac{ -b \pm \sqrt{b^2 - 4ac}}{ 2a }\\x = \frac{ -14 \pm \sqrt{14^2 - 4(3)(-30)}}{ 2(3) }\\x = \frac{ -14 \pm \sqrt{556}}{ 6 }\\x = \frac{ -14 }{ 6 } \pm \frac{2\sqrt{139}\, }{ 6 }\\x = -\frac{ 7}{ 3 } \pm \frac{ \sqrt{139}\, }{ 3 }\\x = 1.59661\\x\approx 1.60$