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Aleksandr-060686 [28]
3 years ago
8

Question 1 :In order to convert this equation to Slope-Intercept Form, you must first isolate y.

Mathematics
1 answer:
Lana71 [14]3 years ago
6 0

Answer:

Step-by-step explanation:

Add -6x to both sides

6x + 7y + − 6x = 14 + − 6x

7y = − 6x + 14

Divide both sides by 7

7y / 7 = − 6x + 14 / 7

y = − 6 / 7x + 2

Answer

y = −6 / 7x + 2

<u>Graph question: answer would be :</u>  

y = \frac{-3}{5}  x+ 2

Place a point on (0,2) and a point on (5, -1)

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Answer:

The answer is below

Step-by-step explanation:

A linear graph has an equation of the form:

y = mx + b,

where y and x are variables, m is the slope (rate of change) of the graph and b is the y intercept (value of y when x is 0).

Given that:

2x -2y = 4 , 3x + 2y = 6

The matrix form of the equation is:

AX = B

A=\left[\begin{array}{cc}2&-2\\3&2\end{array}\right] ,X=\left[\begin{array}{c}x\\y\end{array}\right] ,B=\left[\begin{array}{c}4\\6\end{array}\right] \\\\Therefore:\\\\\left[\begin{array}{cc}2&-2\\3&2\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{c}4\\6\end{array}\right] \\\\\left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{cc}2&-2\\3&2\end{array}\right]^{-1} \left[\begin{array}{c}4\\6\end{array}\right] \\\\

\left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{cc}0.2&0.2\\-0.3&0.2\end{array}\right] \left[\begin{array}{c}4\\6\end{array}\right] \\\\\left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{c}2\\0\end{array}\right]

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