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2 years ago

Does this equation have exactly one solution

Mathematics

1 answer:

Alex73 [517]2 years ago

6 0

Answer:

$13x + 7 = 9x - 33 + 4x \\ 7 + 33 = 13x - 13x \\ \\ 40 = 0 \\ \\ no$

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Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?

Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

8 0

3 years ago

Why can you NOT combine 3x and 5x^2 ?

diamong [38]

Although they are the same variable, you cannot add two variables raised to different powers. 3x^1 + 5x^2 cannot work, but 3x^2 + 5x^2 can. Also, if you are multiplying them, they would combine to be 15x^3, as 3 and 5 (The coefficients) multiply together and x^2 times x^1 = x^3.

I hope that helps.

7 0

3 years ago

15/3 = 5 4_7 + 5 2_3<br> b=?

OLEGan [10]

Answer:

válla si son brutos está bien fácil esa pregunta lo que pasa es que estoy haciendo mi trabajo

5 0

2 years ago

Read 2 more answers

Please help! :))

denis23 [38]

Answer:

Check below

Step-by-step explanation:

Hi,

We're dealing with linear functions. $f(x)=mx+b$

We have here the first function.

$g(x)=3x$

That's a linear function, with slope, and no linear coefficient since

But on the other hand, the functions below, they all describe parallel lines, since their slope has the same value. I've changed the letters to make it easier the comprehension.

Even though each one has the same slope value, they have different non zero linear coefficients, {-6,-18,6,18}. Unlike, the first one

$h(x)=3(9x-2) \rightarrow h(x)= 27x-6\\i(x)=9(3x-2)\rightarrow i(x)=27x-18\\j(x)=3(9x+2)\rightarrow j(x)=27x+6 \\k(x)=9(3x+2)\rightarrow k(x)=27x+18\\$

A possible solution would be adjusting any of these, whose operation would result in g(x)=3x, but

$y=9(\frac{3x}{9}-2)+18 =3x$

4 0

3 years ago

The student council is selling tickets to a school dance. One teacher decides to pay $10 for his class, and the students in the

Lostsunrise [7]

Hi,

x + y = 350 (equation 1)

3x + 2y = 950 (equation 2)

Use Substitution Method

Isolate variable x in equation 1

x = 350 – y (equation 3)

Substitute equation 3 into equation 2

3(350 – y) + 2y = 950

1050 – 3y + 2y = 950

3y – 2y = 1050 – 950

y = 100

Substitute y = 100 into equation 1

x + 100 = 350

x = 250

Answer: 250 $3 tickets and 100 $2 tickets were sold.

8 0

3 years ago

Does this equation have exactly one solution ​

Does this equation have exactly one solution