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3 years ago

A number is 4 hundreds more than 142. What is the number?

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

3 0

Well then multiply 400 x 142 and get your answer of 56,800

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ASAP!! can someone help solve any of these? whoever answers the most gets brainliest, i underlined the questions

Pachacha [2.7K]

Answer:

can u please type out the photo is too dark to see the questions

Step-by-step explanation:

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3 years ago

Two three-digit numbers are made up of six different digits. The first digit of the second number is twice as big as the last di

topjm [15]

Answer:the smallest possible sum of the two numbers is 537

Step-by-step explanation:

Two three-digit numbers are made up of six different digits.

To interpret this, let the two three digit numbers be;

ABC and. DEF

The first digit of the second number is twice as big as the last digit of the first number.

Interpret;

D=2C

The first digit of the first number can be 1, the second digit 0 and the third digit 2.

102.

For the second number:

D=2C

The first digit is 4, second digit 3 and last digit 5 since no repetition of digits

435.

Answer:the smallest possible sum of the two numbers is

102+435= 537

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3 years ago

What is the area of the parallelogram QRST?

jonny [76]

$\text{Area of parallelogram QRST} = QR \times TU = 20 ~in \times 18~in =360 in^2$

8 0

2 years ago

Johnny has 6 apples, 12 bananas and 14 strawberries. write in simplest form.

julsineya [31]

Answer:

a=apples

b=bananas

s=strawberries

6a, 12b, 14s

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

What number must you add to complete the square?<br> x^2 + 2x = -1

Andru [333]

$\large\begin{array}{l} \textsf{You must add 1 to complete the square.}\\\\ \textsf{There is a very common special product: (square of a sum)}\\\\ \mathsf{(a+b)^2=a^2+2ab+b^2}\\\\\\ \textsf{Take the given equation:}\\\\ \mathsf{x^2+2x=-1\qquad(i)}\\\\\\ \textsf{The first term is a square (x squared)}\\\\ \textsf{The second term is a product of 2, x and 1.} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{Back to (i), adding 1 to both sides:}\\\\ \mathsf{x^2+2x+1=-1+1}\\\\ \boxed{\begin{array}{c} \mathsf{(x+1)^2=0} \end{array}} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}$

If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248

$\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}$

6 0

3 years ago

Read 2 more answers