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Lady bird [3.3K]

3 years ago

15

How do you find a rate of a number

2 answers:

KATRIN_1 [288]3 years ago

8 0

To determine the rate of a number do the following steps:

Multiply the number by the percent (e.g. 87 * 68 = 5916)

Divide the answer by 100 (Move decimal point two places to the left) (e.g. 5916/100 = 59.16)

Round to the desired precision (e.g. 59.16 rounded to the nearest whole number = 59)

olchik [2.2K]3 years ago

3 0

ROC is often used when speaking about momentum, and it can generally be expressed as a ratio between a change in one variable relative to a corresponding change in another; graphically, the rate of change is represented by the slope of a line.

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Can someone help me please!!!

Morgarella [4.7K]

Answer: $P=1200x+35000$

Step-by-step explanation:

Given: A town's population has been growing linearly. In 2003, the population was 35000, and the population has been growing by 1200 (constant rate of change) people each year.

The equation of a line is given by :-

$y=mx+c$ , where m is the slope ( constant rate of change) and c is the initial value of the function.

From the given statement , we have the equation for the population x years after 2003 :-

$P=1200x+35000$

6 0

4 years ago

The functions q and r are defined as follows.

UkoKoshka [18]

Q(3) = -2(3)+2 = -4
r(q(3)) = (-4)^2-1 = 15

3 0

3 years ago

A nutrition company is marketing a low calorie snack brownie. A serving size of the snack is 3 brownies and has a total of 50 ca

lozanna [386]

Answer:

350 calories

Step-by-step explanation:

divide 50 by 3 then multiply that number by 21.

3 0

3 years ago

“encontrar la integral indefinida y verificar el resultado mediante derivación”

Oliga [24]

$I=\displaystyle\int\frac x{(1-x^2)^3}\,\mathrm dx$

Haz la sustitución:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{y^3}=\frac1{4y^2}+C=\frac1{4(1-x^2)^2}+C$

Para confirmar el resultado:

$\dfrac{\mathrm dI}{\mathrm dx}=\dfrac14\left(-\dfrac{2(-2x)}{(1-x^2)^3}\right)=\dfrac x{(1-x^2)^3}$

$I=\displaystyle\int\frac{x^2}{(1+x^3)^2}\,\mathrm dx$

Sustituye:

$y=1+x^3\implies\mathrm dy=3x^2\,\mathrm dx$

$\implies I=\displaystyle\frac13\int\frac{\mathrm dy}{y^2}=-\frac1{3y}+C=-\frac1{3(1+x^3)}+C$

(Te dejaré confirmar por ti mismo.)

$I=\displaystyle\int\frac x{\sqrt{1-x^2}}\,\mathrm dx$

Sustituye:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{\sqrt y}=-\frac12(2\sqrt y)+C=-\sqrt{1-x^2}+C$

$I=\displaystyle\int\left(1+\frac1t\right)^3\frac{\mathrm dt}{t^2}$

Sustituye:

$u=1+\dfrac1t\implies\mathrm du=-\dfrac{\mathrm dt}{t^2}$

$\implies I=-\displaystyle\int u^3\,\mathrm du=-\frac{u^4}4+C=-\frac{\left(1+\frac1t\right)^4}4+C$

Podemos hacer que esto se vea un poco mejor:

$\left(1+\dfrac1t\right)^4=\left(\dfrac{t+1}t\right)^4=\dfrac{(t+1)^4}{t^4}$

$\implies I=-\dfrac{(t+1)^4}{4t^4}+C$

4 0

4 years ago

PLEASE ANSWER I NEED THIS ASAP

Rudik [331]

It would also be 42 because the triangle is divided in half.

5 0

4 years ago

Read 2 more answers