Question

If there were 30,000 cars produced a later it was found that 222 had a defect in one of the headlight bulbs, what is the probability that any one of those cars would have the defect?
A. 2/6235
B. 10/520
C. 37/5000
D. 1/5200

Answer 1

Answer:

P(defective) = $\frac{37}{5000}$

Step-by-step explanation:

If there were 30,000 cars produced a later it was found that 222 had a defect in one of the headlight bulbs,

Total cars produced = 30,000

defective cars = 222

Probability ( one of the defective car)= number of defective cars/ total cars produced

P(defective) = $\frac{222}{30000}$

Divide both sides by by 6

222 divide by 5= 37

30000 divide by 5= 5000

P(defective) = $\frac{37}{5000}$

Answer 2

To find the probability of any sample you're studying, you divide the number of objects studied by the total number of the sample. Here, we have 30,000 cars. It has been found that 222 had a defect in one of the headlight bulbs. So 222 of 30,000 cars had a defect. So the probability that any of those cars can have a defect is 222/30,000. You divide both numbers by 5 to simply, and you get 37/5000.
So the probability that any of those cars could have the defect is 37/5000, so 37 cars out of 5000 (Answer C)

Hope this Helps! :)