There's no such thing as the "length"of an angle.
But we know what you're getting at.

You have said that the angles are complementary. If two angles are
complementary, then their sum is 90 degrees, so we can take your
two angles and write:

   <u>x</u> (one angle) plus <u>(2x + 12)</u> (the other one) <u>= 90 degrees

</u><u /> x + 2x + 12 = 90<u>

</u>Subtract 12 from each side:    x + 2x = 78

Add the x's on the left side: 3x    = 78

Divide each side by 3 :    x    = 26 degrees

One angle is 'x' = <em>26 degrees</em>

The other one is (2x + 12) = 52+12 = <em>64 degrees</em>

4 0

4 years ago

pls help me asap and fast and for every question, you have to explain to me how you got the answer the one who did all of the wi

shtirl [24]

Answer:

180-12-35

----------

= 133

----------

3×2×1

----------

2 × 2

=6/4

=3/2

6(2÷3/5)

=6(10/3)

=20

5 0

3 years ago

Simplify the expression

ollegr [7]

Answer:

Step-by-step explanation:

$\dfrac{x^2-8x+12}{x^2-7x+10}\\\\x^2-7x+10\ne0\ \iff\ x=\frac{7\pm\sqrt{49-40}}{2}\ne0\ \iff\ x\ne5\ \wedge\ x\ne2\\\\\\\dfrac{x^2-8x+12}{x^2-7x+10}=\dfrac{x^2-2x-6x+12}{x^2-2x-5x+10}=\dfrac{x(x-2)-6(x-2)}{x(x-2)-5(x-2)}=\\\\\\ =\dfrac{(x-2)(x-6)}{(x-2)(x-5)}=\dfrac{x-6}{x-5}\\\\\\f(x)=x-6\\\\g(x)=x-5$

4 0

3 years ago