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Lemur [1.5K]
3 years ago
10

Which of the following is the complete factorization of 10x - 3 - 3x 2?

Mathematics
1 answer:
andrew11 [14]3 years ago
5 0
-3x^2+10x-3  

This is of the form ax^2+bx+c.  We need to find two values, j and k, such that:

jk=ac=9 and j+k=b=10, so j and k must be 1 and 9.

Now replace bx with jx and kx in the original equation...

-3x^2+x+9x-3  now factor 1st and 2nd pair of terms

-x(3x-1)+3(3x-1)

(-x+3)(3x-1) or equivalently...

-(x-3)(3x-1) or as they put it:

-(3x-1)(x-3)
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List at least three shapes, other than pentagons, in the table. If the shape is a polygon, indicate whether the shape is regular
Sergio [31]

The number of times that the shape will map back onto itself as the shape rotates 360° about its center is 6.

<h3>What is the sum of all the exterior angles of a regular polygon?</h3>

For a regular polygon of any number of sides, the sum of its exterior angle is 360° (full angle).

Regular polygons have all sides the same and that apothem bisects the side in two parts, (provable by symmetry).

A regular polygon with n sides can map onto itself by n times

It will rotate 360°/n about its center every time and will map onto itself

Examples are in the attached table as well as the solution.

The number of times that the shape will map back onto itself as the shape rotates 360° about its center is 6.

Learn more about a regular polygon here:

brainly.com/question/14173422

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3 0
2 years ago
3(2X+3)+2(3X+2)=9X+4
egoroff_w [7]
The answer to this is -3
8 0
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4 0
3 years ago
Factorize completely the expression(h+2k)²+4k²-h²​
julsineya [31]

The expression factorized completely is (h +2k)[(h+2k) + (2k-h)]

From the question,

We are to factorize the expression (h+2k)²+4k²-h²​ completely

The expression can be factorized as shown below

(h+2k)²+4k²-h²​ becomes

(h+2k)² + 2²k²-h²​

(h+2k)² + (2k)²-h²​

Using difference of two squares

The expression (2k)²-h²​ = (2k+h)(2k-h)

Then,

(h+2k)² + (2k)²-h²​ becomes

(h+2k)² + (2k +h)(2k-h)

This can be written as

(h+2k)² + (h +2k)(2k-h)

Now,

Factorizing, we get

(h +2k)[(h+2k) + (2k-h)]

Hence, the expression factorized completely is (h +2k)[(h+2k) + (2k-h)]

Learn more here:brainly.com/question/12486387

5 0
3 years ago
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Find the perimeter of △ABC with vertices A(−5, −5), B(3, −5), and C(−5, 1).
Nitella [24]

Answer:

Perimeter: 24 u

Step-by-step explanation:

In order to find the perimeter of the triangle you have to find the distance between the vertices using the distance formula and add all the distances:

Distance AB

d=\sqrt{ ( x_{2} - x_{1} )^{2} + ( y_{2} - y_{1} )^{2} } \\d=\sqrt{ ( 3 - (-5) )^{2} + ( (-5) - (-5) )^{2} } \\d=\sqrt{ ( 3+5 )^{2} + ( -5+5 )^{2} } \\d=\sqrt{ (8)^{2} + ( 0 )^{2} } \\d=\sqrt{ 64 } \\d=8

Distance BC

d=\sqrt{ ( x_{2} - x_{1} )^{2} + ( y_{2} - y_{1} )^{2} } \\d=\sqrt{ ( -5 - 3 )^{2} + ( 1 - (-5) )^{2} } \\d=\sqrt{ ( -8 )^{2} + ( 1+5 )^{2} } \\d=\sqrt{ (-8)^{2} + ( 6 )^{2} } \\d=\sqrt{64+36} \\d=\sqrt{100}\\d=10

Distance CA

d=\sqrt{ ( x_{2} - x_{1} )^{2} + ( y_{2} - y_{1} )^{2} } \\d=\sqrt{ ( -5 - (-5) )^{2} + ( 1 - (-5) )^{2} } \\d=\sqrt{ ( -5+5 )^{2} + ( 1+5 )^{2} } \\d=\sqrt{ (0)^{2} + ( 6 )^{2} } \\d=\sqrt{36} \\d=6

Adding all the 3 distances we have that:

P=8+10+6=24 u

6 0
3 years ago
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