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mafiozo [28]
2 years ago
15

Solve for g please!!!!!!!!!!!!!!

Mathematics
1 answer:
alexandr402 [8]2 years ago
4 0
G = m/5t- Q^2. Hope that helps.
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How much greater is 4/9 than 2/9. Please answer.
kodGreya [7K]

Step-by-step explanation:

A better way to word this is how much more is 4/9 than 2/9 which is 2/9 more because 2/9 plus 2/9 is 4/9 and the denominator stays the same

4 0
2 years ago
April has only consumed one glass of wine, so her body isn't affected by the alcohol because short-term effects only begin with
MrMuchimi

ANSWER: False

This is false because alcohol can have effect as soon as the first drink, depending on the type of person you are.

For example, if your parents drank, and you were born early (a preemie) this can affect your ability to drink.

Hope this helps! ^^

4 0
3 years ago
Read 2 more answers
44 lb 6 oz = ____ ounces
hodyreva [135]

Answer:

710 oz

Step-by-step explanation:

5 0
2 years ago
After a storm damages the community center, Shanika and her friends hold fundraising events to help pay for repairs. After the f
pantera1 [17]

Answer:

Step-by-step explanation:

The total they want to raise is $2,400 if that is what you're asking?

3 0
2 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0
3 years ago
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