$24.00. 6,000 divided by 500 is 12 times the $2 per 500 is $24
a) We kindly invite to check the image attached below to see a detailed graph of the <em>piecewise</em> function.
b) The <em>piecewise</em> function is continuous.
<h3>How to understand a piecewise function</h3>
A <em>piecewise</em> function is a <em>conditional</em> combination of two or more functions, whose expression depends on which value of the domain is the function evaluated at.
a) The <em>piecewise</em> function described in the question is plotted on a graphing tool (i.e. <em>Desmos</em>), whose result is presented in the image attached below.
b) A function is <em>continuous</em> if and only if there is one value from range for every value of domain. The <em>piecewise</em> function is continuous as <em>linear</em> functions are continuous and the two functions of the <em>conditional</em> combination have the same value for x = 30.
To learn more on piecewise functions: brainly.com/question/12561612
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Answer:
30
Step-by-step explanation:
Hey There!
To find the area of a triangle we divide the product of the height and base by 2
6x10=60
60/2=30
the area of the triangle is 30 :)
Answer:
idk
Step-by-step explanation:
Hi again :)
(3p +2)(5p-1)
Distribute '
(3p)(5p)+(3p)(-1)+(2p=)(5p)+(2)(-1)
15p² - 3p + 10x - 2
15p² + 7p - 2
Thus, the correct option is : C
(5w+2)(8w+5) It says to use the tab, but I don't know :) so I am using my way :)
Distribute
(5w)(8w)+(5w)(5)+(2)(8w)+(2)(5)
40w² + 25w + 16w + 10
40w² + 41w + 10
Thus, The answer is B
Again, I don't know how to solve it by suing the tab. However, I will use my way :)
(-5y+3)(2y+5)
Distribute
(-5y)(2y)+(-5y)(5)+(3)(2y)+(3)(5)
-10y² - 25y + 6y + 15
-10y² - 19y + 15
Thus, the answer is : D
(6x - 5)(2x - 3)
Distribute
(6x)(2x)+(6x)(-3)+(-5)(2x)+(-5)(-3)
12x² - 18x - 10x + 15
12x² - 28x + 15
The answer is : A
For #12 The answer is : C
Now let's solve #13
(4x -6y³)²
Distribute
(4x)(4x)+(4x)(-6y³)+(-6y³)(4x)+(-6y³)(-6y³)
16x² - 24xy³-24xy³+36y^6
36y^6 - 48xy³ = 16x²
The answer is B
wow, that was a lot of work. Good luck!