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klasskru [66]
3 years ago
12

Gareth has $2,000 to invest. Putting the money in a savings account at his local bank will earn him 2.2% annual interest and giv

es him the ability to make ATM withdrawals from that bank’s ATMs. Putting the money in an online savings account will earn him 4.85% annual interest, but he will be charged $3 every time he makes an ATM withdrawal. Assuming that Gareth’s ATM withdrawals do not affect the amount of interest he earns, roughly how many ATM withdrawals must Gareth make every year for the local savings account to be a better deal than the online savings account?
Mathematics
2 answers:
Nonamiya [84]3 years ago
4 0

Answer:

its 14

Step-by-step explanation:

i took the test. I got you

atroni [7]3 years ago
3 0
<span>What a strange question. How could withdrawals fail to change the interest earned?!
 Anyway...
 How much does $2000 earn in a year at 2.2%? How much does $2000 earn in a year at 4.85%? What the difference in interest credits? How many $3 ATM transactions does it take to eat that up?</span>
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52(7)^1/5<br><br> Need help solving this problem. I don’t have Ti-84 Calculator yet
frozen [14]

Answer:

52 \sqrt[5]{7}

Step-by-step explanation:

52(7 {)}^{ \frac{1}{5} }

= 52 \sqrt[5]{7}

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3 years ago
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Artyom0805 [142]

Answer:

$5

Step-by-step explanation:

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3 years ago
Find the area of a circle with<br>radius, r = 5.52m.<br> answer rounded to 2 DP.​
Mice21 [21]

Answer:

Step-by-step explanation:

Formula = A=πr2

Putting values in the equation

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7 0
3 years ago
Read 2 more answers
There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In
Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

P(0.45

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

P(p>0.8)=P(z>z^*)

The z value is calculated as before:

z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0
3 years ago
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mash [69]

Answer:

  • 18 miles

Step-by-step explanation:

Distance = speed * time

  • d = 12 *1 1/2 = 12*1.5 = 18
5 0
3 years ago
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