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3 years ago

True or false Exterior angles are the angles created when the sides of the triangle are shortened.

Mathematics

1 answer:

Naddika [18.5K]3 years ago

8 0

Answer:

The statement is false. Exterior angles are the angles created when the sides of the triangle are extended

Step-by-step explanation:

In order to find the exterior angle of a polygon, the side of the polygon is extended to go past the vertex of the polygon to form an angle adjacent and supplementary to the the interior angle of the polygon at the vertex of the polygon where the exterior angle is formed.

The sum of the exterior angle and the adjacent interior angle is equal to 180°

The exterior angle can also be described as being formed by one side of a polygon and an extension of the adjacent side to previous side of the same polygon and it can also be referred to as a turning or an external angle.

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[HELP] For j(x) = <img src="https://tex.z-dn.net/?f=5%5Ex%5E-%5E3" id="TexFormula1" title="5^x^-^3" alt="5^x^-^3" align="absmidd

Alina [70]

The difference quotient of the function that has been presented to us will turn out to be 5.

<h3>How can I calculate the quotient of differences?</h3>

In this step, we wish to determine the difference quotient for the function that was supplied.

To begin, keep in mind that the difference quotient may be calculated by:

Lim h->0 $\frac{f(x+h)-f(x)}{h}$

Now, for the purpose of the function, we need this:

Then we will have:

$\begin{aligned}&\lim _{h \rightarrow 0} \frac{j(x+h)-j(x)}{h} \\&\lim _{h \rightarrow 0} \frac{5 *(x+h)-3-5 * x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 x+5 h-3-5 x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 h}{h}=5\end{aligned}$

j(x) = 5x - 3

Then the following will be true:

Therefore, 5 is the value of the difference quotient for j(x) is %

Read the following if you are interested in finding out more about difference quotients:

brainly.com/question/15166834

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6 0

11 months ago

What is x+y <3 (0,0)

larisa [96]

The expression is a bit invalid. You can't add variables by variables.

3 0

3 years ago

Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0

3 years ago

Find the unknown angle measure.

Fofino [41]

Answer:

58 degrees

Step-by-step explanation:

add the 2 shown, 74+48, to get 122 all triangles add up to 180 so subtract 122 from 180 and you get 58

7 0

3 years ago

Read 2 more answers

The point p(-3,2) is translated up 3 and right 4. what are the coordinates of p

monitta

Answer:

P'(1, 5)

Step-by-step explanation:

Up 3 is vertical movement, so it changes the y-value: 2 + 3 = 5

Right 4 is horizontal movement, so it changes the x-value: -3 + 4 = 1

6 0

3 years ago