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AURORKA [14]
3 years ago
7

The graph of a quadratic function

Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

A

The leading coefficient is negative.

Step-by-step explanation:

Quadratic equation:

A quadratic equation has the following format:

y = ax^2 + bx + c

The leading coefficient is a.

a negative:

The graph of the function is concave down, that is, it displays values that approach  negative infinity.

a positive:

The graph of the function is concave up, that is, it displays values that approach  up infinity.

In this question:

Displays values that approach  negative infinity, so the leading coefficient is negative, and the correct answer is given by option A.

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Divide 33 photos into 2 groups so the ratio is 4 to 7.
kvv77 [185]
So you want two groups that are in a ratio of 4 to 7
so 33=4x+7x
so 33=11x
so x=3

that means the groups are 4*3= 12 and 7*3=21
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I have an 88 in my math class, according to my teacher if I get a 75% on my final exam my grade will be 86. my final exam is wha
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Connor had 37 green marbles. Then he bought 3 bags of blue marbles. There were 6 marbles in each bag. How many marbles does Conn
ycow [4]

Answer:

55 marbles.

Step-by-step explanation:

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Sibal started with $500 in a bank account that does not earn interest. In the middle of every month, she withdraws 1/5 of the ac
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5 0
4 years ago
Can someone help me plz .. Use these lengths to find cos B, tan B, and sin B.
lara [203]

Answer:

cos B = \frac{7}{25}

tan B = \frac{24}{7}

sin B = \frac{24}{25}

Step-by-step explanation:

In the right triangle, there are three sides and 2 acute angles

  • Hypotenuse ⇒ the opposite side of the right angle
  • Leg1 and Leg 2 ⇒ the sides of the right angle

The trigonometry functions of one of the acute angles Ф are

  • sin Ф = opposite leg/hypotenuse
  • cos Ф = adjacent leg/hypotenuse
  • tan Ф = opposite leg/adjacent leg

In Δ ACB

∵ ∠C is the right angle

∴ AB is the hypotenuse

∵ AC is the opposite side of ∠B ⇒ leg1

∵ CB is the adjacent side of ∠B ⇒ leg2

→ By using the ratios above

∴ cos B = \frac{CB}{AB} , tan B = \frac{AC}{CB} , sin B = \frac{AC}{AB}

∵ CB = 7, AB = 25, AC = 24

∴ cos B = \frac{7}{25}

∴ tan B = \frac{24}{7}

∴ sin B = \frac{24}{25}

6 0
3 years ago
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