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Jobisdone [24]
3 years ago
11

Use a graph to solve this equation. th 2x2–5=-X? + 2x – 1

Mathematics
1 answer:
solong [7]3 years ago
4 0

Answer:

X + 2= 0

X - 4  > 7

-4 + y = 3y + 4 (y - 3)

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Can anyone help plz plz
vladimir2022 [97]

Answer:

the first choice

Step-by-step explanation:

- 5 {x}^{2}  + 7x + 3

3 0
3 years ago
A square has side lengths of (4x+5) inches.Write an expression to represent the perimeter of the rectangle.Then find the perimet
Marat540 [252]

Answer:

68 inches

Step-by-step explanation:

P = 2 (L + W)

P = 2(4x+5 + 4x+5)

P = 2(8x + 10)

P = 16x + 20

If x= 3

P = 16(3) + 20

P = 48 + 20

P = 68 inches

3 0
3 years ago
F your car gets 2424 miles per​ gallon, how much does it cost to drive 370370 miles when gasoline costs ​$3.203.20 per​ gallon?
TiliK225 [7]
$351,912.62 would be the cost
4 0
3 years ago
Part 1. Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are in
dem82 [27]

There is no b unfortunately

Find inverse of x+a

  • x+a=y

interchAnge

  • y+a=x
  • y=x-a

Inverse is

  • f^{-1}x=x-a

Now

  • x-a=cx-d
  • x-cx=a-d
  • x(1-c)=a-d
  • x=a-d/1-c

So

You can have any number according to this but

  • c must not be 1
  • a and d must not be equal .
  • All three should belongs to integers set

Note:-

As there is no b given in question (May be missed in typing) Part-2 's equation can't be executed and part 3 also

5 0
2 years ago
Victor drew trapezoid PQRS on a coordinate plane p(7,4) q(10,4) r(13,-1) s(8,-1) what is length in units of side ps
olga nikolaevna [1]

Answer:

PS=\sqrt{26}units

Step-by-step explanation:

Given : PQRS is a trapezoid on a coordinate plane P(7,4) Q(10,4) R(13,-1) S(8,-1).

To find:: Length of the side PS

Solution : Using the distance formula, we can find the length of the side PS, therefore

PS=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2}

PS=\sqrt{(-1-4)^{2}+(8-7)^2 }

PS=\sqrt{(-5)^2+(1)^2}

PS=\sqrt{25+1}

PS=\sqrt{26}units

which is the required length of the side PS.

5 0
3 years ago
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