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Annette [7]
3 years ago
10

Assuming that the actual process ids of the parent and child process are 2600 and 2650 respectively, what will be printed out at

lines A, B, C, D, E, and F? Be sure to explain your answers. int main() { pid_t x, y; int value = 90; value += 30; /* fork a child process */ x = fork(); if (x < 0) { /* error occurred */ fprintf(stderr,"Fork failed"); return(1); } else if (x == 0) { /* child process */ y = getpid(); printf("child: x = %d",x); /* A */ printf("child: y = %d",y); /* B */ value += 20; printf("child: value = %d\n", value); /* C */ exit(0); } else { /* parent process */ y= getpid(); printf("parent: x = %d",x); /* D */ printf("parent: y = %d",y); /* E */ wait(NULL); printf("parent: value = %d\n", value); /* F */ } }
Computers and Technology
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

Output explanation to the given code can be defined as follows:

Explanation:

In A the output is 0 , It will return fork value of the child process that is 0. so, 0 is printed during child process.  

In B the output is 2650 , in which the getpid() method returns the child process id  value that is 2650.  

In C the output is 140, As it is declared in key, all process have their own "value" copies. 20 are inserted during childhood, so 140 are written.  

In D the output is 2650, its fork() method returns the child ID to the parent process. so the value 2650 is printed.  

In E the output is 2600, Its getpid() method will returns parent process id  that is equal to 2600.  

In F the output is 120 Since the value is declared in primary, all process so their own "value" copies. 120 will be printed during process.

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Answer:

oid changeCase (char char_array[], int array_size ) {

__asm{

   mov eax, char_array;    

   mov edi, 0;

readArray:

   cmp edi, array_size;

   jge exit;

   mov ebx, edi;          

   shl ebx, 2;

   mov cl, [eax + ebx];    

check:

   //working on it

   cmp cl, 0x41;      

   jl next_indx;

   cmp cl, 0x7A;      

   jg next_indx;

   cmp cl, 'a';

   jl convert_down;

   jge convert_up;

convert_down:

   or cl, 0x20;        //make it lowercase

   jmp write;

convert_up:

   and cl, 0x20;      

   jmp write;

write:

   mov byte ptr [eax + ebx], cl    

next_indx:

   inc edi;

exit:

   cmp edi, array_size;

   jl readArray;

mov char_array, eax;

}

}

Explanation:

  • Move char_array to eax as it is base image .
  • Use ebx as offset .
  • Use ecx as the storage register .
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6 0
3 years ago
A ____ resembles a circle of computers that communicate with each other.
Sidana [21]

Answer:

ring network

Explanation:

In a ring network, the nodes are arranged in a circular pattern where each node is connected to two adjacent nodes. In this topology, any node can communicate with any other node via the intermediaries.

In comparison,

- in a star network every communication needs to pass through a central hub node

- in a bus, each node is connected to a shared linear communication bus.

- in a hierarchical network nodes are organized along a tree structure layout.

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3 years ago
SHOW ME SOME C++ TUTORIALS?
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Answer:

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Explanation:

3 0
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Answer:

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