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3 years ago

Simplify the expression 3(x + 2)(x2 − x − 8).

Mathematics

1 answer:

expeople1 [14]3 years ago

8 0

Answer:

3x^3+3x^2-30x -48

Step-by-step explanation:

we apply distributive property

3(x + 2)(x^2 − x − 8)

so we have:

(3*x+3*2)(x^2 − x − 8)

(3x+6)(x^2 − x − 8)

3x*x^2 - 3x*x -3x*8 + 6*x^2 -6*x -6*8

3x^3-3x^2-24x +6x^2 -6x -48

3x^3+3x^2-30x -48

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(v3-2v2-14v-5) ÷ ( v+3) What is the solution? Is dividing polynomials

HACTEHA [7]

This can be done using synthetic division.

1 -2 -14 -5
-3 -3 15 -3
___________
1 -5 1 -8
v^2 - 5v + 1 remainder -8
OR
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4 years ago

The solution to the equation log2x + log2(x – 6) = 4 is x =

GenaCL600 [577]

Answer:

Value of x=8

Step-by-step explanation:

Given : $log_2x+log_2(x-6)=4$

To find : The solution to the equation given

Solution :

Step 1- Write the given expression

$log_2x+log_2(x-6)=4$

Step 2 - Using logarithmic laws

$log_{b}x+log_by=log_bxy$

$log_2(x)(x-6)=4$

Step 3 - To remove log-base 2, we need to raise the left and right hand terms to power 2.

$(x)(x-6)=2^4$

$x^2-6x-16=0$

Step 4 - Solve the quadratic equation

$x^2-8x+2x-16=0$

$x(x-8)+2(x-8)=0$

$(x-8)(x+2)=0$

Either x=8 or x=-2

We neglect x=-2 because negative value is not defined in log.

Value of x=8

6 0

4 years ago

Read 2 more answers

The u.s. department of health and human services collected sample data for 772 males between the ages of 18 and 24. that sample

soldier1979 [14.2K]

The 99% confidence interval for the true mean is given by:

$\bar{x}\pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

where:

$\bar{x}$ is the sample mean = 69.7
$\sigma$ is the standard deviation = 2.8
$z_{\alpha/2}$ is the test statistics = 2.58 for for 99% confidentce interval.
n is the sample size = 772.

Therefore, the 99% confidence interval is:

$69.7\pm2.58\left( \frac{2.8}{\sqrt{772}} \right)=69.7\pm2.58(0.1008) \\ \\ =69.7-0.26\leq\mu\leq69.7+0.26 \\ \\ =69.44\leq\mu\leq69.96$

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3 years ago

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Tanya [424]

Answer:

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Step-by-step explanation:

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3 years ago

What is the answer I need help i still dont understand area

krok68 [10]

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3 years ago