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Sergeu [11.5K]
3 years ago
13

What is the slope-intercept form of the linear equation 2x–8y=322x–8y=32 ?

Mathematics
1 answer:
gladu [14]3 years ago
5 0
2x - 8y = 32
-8y = -2x + 32
y = (-2/-8)x - 32/8
y = 1/4x - 4 <== slope intercept form
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21:28 = :24<br><br>plz help....​
gavmur [86]

Answer:

x=18

Step-by-step explanation:

21:28=x:24

1. rewrite: 21/28 = x/24

2. simplify: 3/4=x/24

3. multiply 24 to both sides: x=18

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2 years ago
A closed cylindrical tank has a height of 200 cm and a diameter of 126 cm
olasank [31]

Area of the sheet used to make the tank = total surface area of the cylinder = 2\pir(r+h) = 2 x 22/7 x 63 x 263 = 104148 sq. cm.

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ANSWER QUICK PLEASE THANK YOU!!! 7 1/2 divided by (4 1/2 - 5 1/8)=
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Answer:

7 1/2 divided by (4 1/2 - 5 1/8)=-12

Step-by-step explanation:

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Answer is -12

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What is the slope of the line that goes through the points (1,-5) and (4,1)?
Anna007 [38]

Answer:

D. 2

Step-by-step explanation:

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3 years ago
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A student solves the following equation and
Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}

\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)

\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)

\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)

as

  • \frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)
  • -\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a
  • \frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2

so equation becomes

3\left(a-2\right)-6a=a+2  

-3a-6=a+2

-3a-6+6=a+2+6

-4a=8

\mathrm{Divide\:both\:sides\:by\:}-4

\frac{-4a}{-4}=\frac{8}{-4}

a=-2

\mathrm{Verify\:Solutions}

\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}

\mathrm{Solve\:}\:a+2=0:\quad a=-2

\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2

\mathrm{Solve\:}\:a-2=0:\quad a=2

So the following points are undefined

a=-2,\:a=2

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0
3 years ago
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