Answer:
~8.66cm
Step-by-step explanation:
The length of a diagonal of a rectangular of sides a and b is
in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:
Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths 
is
So the solution here is
Hello there.
<span>Fifty- three students from 32 different schools signed up for a multi-classroom project. About how many students signed up for the project?
</span><span>B. about 1,800 students
</span>
Answer:
127.17 cm²
Step-by-step explanation:
- Area of a semicircle: 1/2*π*r²
- π (pi) = 3.14
- r (radius) = d (diamater) / 2 => 18/2 = 9 cm
A = 1/2*π*r²
A = 1/2*3.14*9²
A = 1/2*3.14*81
A = 3.14*40.5
A = 127.17 cm²
Therefore, the area of the semicircle is 127.17 cm²
Hope this helps!
48 girls are there. Given that there is a ratio of boys to girls of 7:8. Then divide 42 boys by 7 boys which equals 6. After, multiply 6 by 8 girls equals 48 girls.
Look at the table and find the X value for when both f(x) and g(x) are the same,
They are the same when X is -1 and when x is 0
The two answers would be X = -1 and x = 0
