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lina2011 [118]
3 years ago
14

a. I have five coins in my pocket – four are fair, and the other is weighted to have a 70% chance of coming up heads. I pull one

out at random and flip it three times. What is the conditional probability that I get four heads given I pulled out the weighted coin?
Mathematics
1 answer:
zimovet [89]3 years ago
7 0

Answer:

The conditional probability that I get four heads given I pulled out the weighted coin = 0.2401

Step-by-step explanation:

Probability of getting 4 heads from 4 trials for a fair coin = 0.5⁴

But given that it is the weighted coin that is pulled out,

The probability of getting 4 heads from 4 trials = 0.7⁴ = 0 2401

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A mean equal to 5 cm. A simple random sample of wrist breadths of 40 women has a mean of 5.07
neonofarm [45]

Answer:

The value of the test statistic is z = 1.34

Step-by-step explanation:

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

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This means that the null hypothesis is \mu = 5

A simple random sample of wrist breadths of 40 women has a mean of 5.07 cm. The population standard deviation is 0.33 cm.

This means that n = 40, X = 5.07, \sigma = 0.33

Find the value of the test statistic?

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5 0
3 years ago
Suppose that y is directly proportional to x, and y = 150 when x = 15. What is the constant of proportionality?
galina1969 [7]

Answer:  The required constant of proportionality is 10.

Step-by-step explanation:  Given that y is directly proportional to x, and y = 150 when x = 15.

We are to find the constant of proportionality.

According to the given information, we can write

y\propto x\\\\\Rightarrow y=kx~~~~~~~~~~~~~~~~[\textup{where k is the constsnt of propotionality}].

When y = 150 and x = 15, we get from the above equation that

y=kx\\\\\Rightarrow 150=k\times15\\\\\Rightarrow k=\dfrac{150}{15}\\\\\Rightarrow k=10.

Thus, the required constant of proportionality is 10.

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2 years ago
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