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8_murik_8 [283]
3 years ago
10

Answer number 2 plz plz plz

Mathematics
1 answer:
Bingel [31]3 years ago
7 0
Ok so the answer is Choice b
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What is the approximate volume of a cone with a height of 12 in. and radius of 9 in.?
Arisa [49]
Volume of the cone = 1/3π r^2 h
So, we are given that r = 9 and h = 12
plugging in all the known values 
1/3 * (3.14) * 9 * 9 * 12
= 1017.36 cm³
or
≈1017.4 cm³
8 0
3 years ago
56 points for whoever answers correctly !
vladimir2022 [97]

We need to use what we know about rectangles to get:

1)

  • Total length = 2*W + 8ft
  • Total width = W + 8ft

2) area = 2*W^2 + 24ft*W + 64ft^2

<h3>Working with rectangles:</h3>

We know that rectangles are defined by two measures, width W and length L.

Here we do know that the length of the pool is twice the width, and the width is W, then the length of the pool is:

L = 2*W

And we also have a sidewalk of 4ft all around the pool, now we want to get:

1) The total length and the total width.

This will be equal to the length/width of the pool <u>plus twice the width of the sidewalk</u> (we add it twice because is in both ends) then we have:

  • Total length = L + 2*4ft = 2*W + 8ft
  • Total width = W + 2*4ft = W + 8ft

2) Now we want to get an expression for the total area of the pool.

Remember that for a rectangle the area is just the product between the width and the length, so to get the area of the pool with the sidewalk we just take:

area = (total length)*(total width)

area = (2*W + 8ft)*(W + 8ft) = 2*W^2 + 3*W*8ft + 64ft^2

area = 2*W^2 + 24ft*W + 64ft^2

This is the equation that gives the total area as a function of W, the width of the pool.

If you want to learn more about rectangles, you can read:

brainly.com/question/17297081

6 0
3 years ago
Find x!!! pls fast !! see photo for question
vazorg [7]

I believe that the answer would be 45

5 0
3 years ago
Lorraine writes the equation shown.
Levart [38]

Answer:

a relation and a function

= A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Answer please, thanks.
Rudik [331]
A) The perimeter is the length around the rectangle, so it would be 2 + 5 + 2 + 5 = 14m

The area is 2m * 5m = 10m^2

b/c) You have to draw a rectangle with a perimeter of 14m, and an area that ISN'T 10m^2. You could draw a 3m by 4m rectangle which would have a perimeter of 14m and an area of 12m^2.
4 0
3 years ago
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