Answer:
1st
Vertex
we have
f(x)=x²-18x+88
let
y=x²-18x+88
comparing above equation with ax²+bx+c
we get
a=1
b=-18
c=88
now
vertex(x,y)=(-b/2a,f(-b/2a))
x=(18/2×1)=9
y=f(9)=9²-18×9+88=7
SO
VERTEX(X,Y)=(9,7)
=
Answer:
Step-by-step explanation:
7. 6 + 1/2 + 1/2 = 7
8. shade it
9. 1.3 + 0.2 + 0.4 = 1.9 0.8 + 0.2 + 0.7 = 1.7
10. (2)(4)(5) = 40
(4)(5)(1) = 20
(5)(6)(0) = 0
hope dis helps ^-^
You do C = πd which it would be 69.08
Answer:
i think D is the correct answer
Step-by-step explanation:
1. Let m∠ABK=x°. Since line BK bisects ∠ABD, then
m∠ABK=m∠KBD=x°.
Also m∠ABD=m∠ABK+m∠KBD=2x°.
2. The diagonal BD of rhombus ABCD bisects ∠ABC, then
m∠ABD=m∠DBC=2x°.
This gives you that
m∠ABC=4x°.
3. Angles A and B are supplementary, so
m∠A+m∠B=180°,
m∠A=180°-4x°.
4. Consider triangle ABK. The sum of the measures of interior angles in triangle is always 180°, thus
m∠A+m∠ABK+m∠AKB=180°,
m∠AKB=180°-x°-(180°-4x°),
m∠AKB=3x°=3m∠ABK.
