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Brilliant_brown [7]
3 years ago
9

The solution to a system of equations is (6-3). Choose two equations that might make up the system. Y= -3x+6 Y=2x-9 y=-5x+27 y=2

x-15 y=-4x+27

Mathematics
1 answer:
MakcuM [25]3 years ago
6 0

Answer:  C) y = -5x + 27     and       D) y = 2x - 15

<u>Step-by-step explanation:</u>

Substitute x = 6 and y = -3 into each of the given equations to see which result in a TRUE statement.

A) y = -3x + 6

  -3 = -3(6) + 6

  -3 = -18 + 6

  -3 = -12     FALSE

B) y = 2x - 9

  -3 = 2(6) - 9

   -3 = 12 - 9

   -3 = 3     FALSE

C) y = -5x + 27

  -3 = -5(6) + 27

  -3 = -30 + 27

  -3 = -3    TRUE!

D) y = 2x - 15

  -3 = 2(6) - 15

  -3 = 12 - 15

  -3 = -3    TRUE!

E) y = -4x + 27

  -3 = -4(6) + 27

  -3 = -24 + 27

  -3 = 3   FALSE

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3 years ago
A coin is tossed 4 times. Let E1 be the event "the first toss shows heads" and E2 the event "the second toss shows heads" and so
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Answer:

The events are independent.

The probability of showing heads on both toss is equal to 1/2

Step-by-step explanation:

The sample space for this experiment consists of 2⁴= 16 sample points, as each toss can result in two outcomes we assume that the events are equally likely.

Two events are independent in the sample space if the probability of one event occurs, is not affected by whether the other event has or has not occurred.

In general the k events are defined to be mutually independent if and only if the probability of the intersection of  any 2,3,--------, k  equals the product of their respective probabilities.

P (A∩B) = P(A). P(B)

P (A∩B)   = 1/2. 1/2= 1/4

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So the events are independent.

The probability of showing heads on both toss is equal to 1/2

The sample space for this experiment consists of 2⁴= 16 sample points, out of which eight will have heads on both toss.

Or in other words ( 1/4* 1/4) = 2/4 = 1/2

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3 years ago
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RideAnS [48]

Answer:

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Step-by-step explanation:

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- <em>Look to the attached graph for more understand</em>

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